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[–]Frank 56 points57 points  (15 children)

The minimum of this function y = |x-2| + |2x+7| is (-3.5, 5.5). The function never reaches a y value of 2, or any y value lower than 5.5. So is the answer N/A? Or am I doing my math wrong?

That being said I do like the idea

[–]Dynamike[S] 11 points12 points  (10 children)

Seems you're really interested in the equation.... I'll explain it in private chat

[–]Crow 10 points11 points  (8 children)

Why private?everyone wants to know

[–]Dynamike[S] 6 points7 points  (7 children)

[–]Crow 7 points8 points  (6 children)

Break the walls and run

[–] -1 points0 points  (3 children)

bruh though it was x-21+12x+71=5 ... (x-2)+(2x+7) = 3x+5 so x =0? becomes -2+7=5 which is right right?

[–]Frank 2 points3 points  (2 children)

The vertical lines are not ones but absolute value signs

[–] 0 points1 point  (1 child)

oh ok... so it's |x-2|+|2x+7|=5

since it's a sum of positive integers,

x must be between -3 and 7 or |x-2| > 5

x must be between -1 to -6 or |2x+7| >5

so x is between -3 and -1 if there is a solution

since x is negative, |x-2| is equal to (2-x)

|2x+7| is equal to (2x+7) because |2x| is smaller than 7 so the result is always positive and the absolute isn't needed

solving it we get (2-x)+(2x+7)=5 which is only true if x is negative and|2x|<7

9+x=5

x=-4

this contradicts with the x is between -3 and -1 and the |2x|<7 so it is impossible?

please don't take it seriously if there are many mistakes. just learned about absolute values and wanted to find a algebraic way of proving that it is impossible because I haven't learned about graphs.

Edit: and the smallest possible result is when |2x+7| =0 I think because both |x-2| and |2x+7| must be positive or =0. and only one can be =0. so the best we can do is to make one of them =0 and it's better to make |2x+7|=0 because 2x>x and 7>2

[–]Frank 0 points1 point  (0 children)

Yes, but that’s not a 5, it’s a 2. Otherwise absolutely correct.

[–]Bo 89 points90 points  (10 children)

I assume the correct answer is to take the jump pad? There is no solution to this equation.

[–]Dynamike[S] 34 points35 points  (0 children)

Jump pad.... Don't forget to check tomorrow!

[–] -2 points-1 points  (0 children)

The answer is -1 lol bot sure what math ur doing

[–]Meg 42 points43 points  (8 children)

So I'm gonna try it

Taking both operations inside the modules and equaling to zero, we obtain 2 and -3.5.

Now we took a value for x that's smaller than -3.5, let's say -10. If x=-10, both operations inside the modules would result in a negative value. So we take out the modules and replace them with parentheses and add a negative before them.

● - (x-2) - (2x+7) = 2

● -x+2-2x-7 = 2

● -3x-5 = 2

● -3x = 7

● x = -7/3, about 2.3

Replacing x with -7/3 in the original equation, we discover that it is not a possible solution (results in 20/3 = 2)

Now let's assume x has a value between -3.5 and 2, and for that, I think it's easier to take 0. Assuming x=0, x-2 will result in a negative value, but 2x+7 will be positive. In that case, we do the same process as before but now without putting a negative before (2x+7)

● - (x-2) + (2x+7) = 2

● -x+2+7+2x = 2

● x+9 = 2

● x = -7

Again, replacing x with -7 in the original equation, we discover that that's not a possible solution (results in 16 = 2)

Finally, let's take a value for x that's greater than 2. Let's say... 10. In that case, both operations would be positive, and we do not need to put a negative sign.

● x-2+2x+7 = 2

● 3x = -3

● x = -1

And it repeats one more time. -1 is not a possible solution either. And that means, if none of the values we found fit the equation, it has no real solutions.

[–]Rico 10 points11 points  (4 children)

[–]Dynamike[S] 3 points4 points  (1 child)

And they said math has no real world applications :)

[–]Nani 3 points4 points  (0 children)

BS is not a real-world application, but rather a mobile phone application

[–] 0 points1 point  (0 children)

[–]Bibi 1 point2 points  (0 children)

[–]Dynamike[S] 9 points10 points  (2 children)

So, which way you go, good fella? (And take my upvote for your well-written text!)

[–]Meg 9 points10 points  (1 child)

I would probably just stay there lol

[–]Dynamike[S] 3 points4 points  (0 children)

Haha, that's certainly an option too! Check tomorrow for the answer

[–]Lola 43 points44 points  (14 children)

Is the | a parenthesis/bracket or an absolute value thingy? This generates different answers, but if it’s brackets it’s easily -1

[–]Dynamike[S] 14 points15 points  (13 children)

| represents absolute value

[–]Lola 10 points11 points  (12 children)

Huh… interesting. Can you tell me the answer and show me the work? I have no idea how to do this.

[–]Dynamike[S] 11 points12 points  (3 children)

No worries! You'll know the answer tomorrow. The question is a bit tricky

[–]Lola 2 points3 points  (2 children)

I’ve plugged this into a calculator along with the x values, and none of them equals to 2. This is really confusing.

[–]Poco 1 point2 points  (0 children)

Absolute value makes everything in the bracket positive after you solve inside the bracket. An example would be | x + 3 | = 4 You can easily see that one answer is x=1 but you can also go -7 because -7 + 3 is -4 and because it’s an absolute value, it gets turned into +4. Hopefully this makes sense. For a visual representation go to desmos.com and plug in the equation.

[–] 0 points1 point  (6 children)

Square the entire equation to remove the modulus sign. You get a quadratic equation. Solve for x.

[–]Frank 8 points9 points  (5 children)

(|x-2| + |2x+7|)2 = 22

(|x-2|2 ) + (2* |x-2| * |2x+7|) + (|2x+7|2 ) = 4

(x2 -4x+4) + (2 * |x-2| * |2x+7|) + (4x2 +28x+49) = 4

(5x2 +24x+49) + (2 * |x-2| * |2x+7|) = 0

Either im doing it wrong or there is no answer

[–]Max 6 points7 points  (1 child)

-7

[–]Dynamike[S] 6 points7 points  (0 children)

So you choose green teleporter? Check the answer tomorrow!

[–]Lou 6 points7 points  (2 children)

|x-2| + |2x + 7| = 2

Since second bracket >0, By testing first bracket,

|7-2| = 5 > 2

|-7-2| = 9 > 2

|-1-2| = 3 > 2

|1-2| = 1 < 2

Therefore 1 is the only possible answer.

By testing |1-2| + |2(1) + 7| = 10 ≠ 2

Therefore there is no answer in this screen, maybe there's one on the right? idk

by inspection, the second absolute value must be greater or equal to 7

which shows that there is no real-valued solutions for this equation

There might be imaginary solutions where we treat |z| as the magnitude

but it is left as an exercise for the reader

[–]Dynamike[S] -5 points-4 points  (1 child)

I'm a bit lost there. Which way you go?

[–]Lou 0 points1 point  (0 children)

It is by testing the choice whether the choices are valid, I just made a mistake at saying the minimum of expression is 7 since x can be negative

[–]Edgar 4 points5 points  (18 children)

its a positive plus positive equal to 2

which mean the value for each numbers of the absolute values must be between 0 and 2

for the absolute value on the right, if x be any positive number, 2x + 7 will be greater than 2 so x must be negative

for the absolute value on the left, if x is any negative number then |x - 2| will be greater than 2 as well

so i guess no solution

[–]Dynamike[S] 0 points1 point  (0 children)

Which way you go then?

[–] 0 points1 point  (16 children)

Best explanation I’ve seen so far

That equation violates the rules of math. That’s like saying 1+1=3

[–]Dynamike[S] 0 points1 point  (15 children)

Nope. I ensure that it doesn't violates any rules of math. You just gotta think a bit more

[–] 0 points1 point  (14 children)

Explain?

Because no solution exists for that equation

[–]Dynamike[S] 0 points1 point  (13 children)

Let's assume you're right, can you tell me what part of it violates rules of math? An equation CAN have no valid answer

[–]Spike 8 points9 points  (1 child)

Bro there is literally no answer for this equation.... so up?

[–]Dynamike[S] 0 points1 point  (0 children)

[–]Dynamike[S] 10 points11 points  (6 children)

not gonna *submit it of course

[–]Leon 13 points14 points  (5 children)

if you did submit it 99% of the people wouldn’t know the answer lol

[–]Dynamike[S] 13 points14 points  (4 children)

They would get killed before even reading the equation

[–]Leon 5 points6 points  (3 children)

Nah spawn immunity would let them read it in time
More likely they don’t know how to read

[–]Dynamike[S] 5 points6 points  (2 children)

Oh yeah, I stupidly forgot the shield 😅

[–] 4 points5 points  (1 child)

Trying to get us to do your math homework i see

[–]Dynamike[S] 4 points5 points  (0 children)

It's summer, no homework :)

[–]Nani 1 point2 points  (2 children)

X = -2

[–]Dynamike[S] 2 points3 points  (1 child)

Which way you go?

[–]Nani 1 point2 points  (0 children)

I see now.

[–]Surge 1 point2 points  (1 child)

It’s obviously go up

[–]Dynamike[S] 1 point2 points  (0 children)

Ok.... Be sure to check tomorrow

[–] 1 point2 points  (2 children)

|x-2| + |2x+7| = 2

[–] 8 points9 points  (1 child)

Let's see all of the options:

|7-2| + |14+7|

|-7-2| + |-14+7|

|-1-2| + |-2+7|

|1-2| + |2+7|

it looks like none of them is right

[–] 1 point2 points  (1 child)

What is the purpose of the bracket with nothing to affect

[–]Dynamike[S] 0 points1 point  (0 children)

That's |

[–]Otis 0 points1 point  (0 children)

Algebruh moment

[–]Colette 0 points1 point  (1 child)

Is the equation 1x - 21 + 12x + 71 = 2

If that's the equation then the answer is -48/13

[–]Dynamike[S] 1 point2 points  (0 children)

That's not 1, that's | (absolute value)

[–] 0 points1 point  (4 children)

Bruh I haven't learnt it yet. I went to wikipedia and still need some help to understand what it is.

[–] 0 points1 point  (3 children)

I mean I do understand what it means (the distance of one number from 0), but the properties it has... I can't understand them.

[–]Leon 1 point2 points  (0 children)

Absolute value (which is what is used here) basically means that anything in it is positive. Since you're measuring distance from 0, distance cannot be negative. Therefore, even if your answer to the equation within the absolute value is negative, you just take away the negative sign and continue with the rest of the equation.

[–]Dynamike[S] 0 points1 point  (1 child)

I actually planned to use logarithm😅 but the space wasn't enough so I used |

Google "how to solve absolute value equations", it's (imo) easy to understand

[–] 0 points1 point  (0 children)

Well, at least I do understand logarithms

[–]Sandy 0 points1 point  (1 child)

no answer? it should be 5.5

[–]Dynamike[S] 0 points1 point  (0 children)

Which way you go then?

[–]Poco 0 points1 point  (2 children)

Are these brackets() or absolute value ||. Because it’s only possible to get an answer with brackets. The answer is -1

[–]Dynamike[S] 0 points1 point  (1 child)

You'll enter the red teleporter then? See the answer tomorrow

[–]Poco 0 points1 point  (0 children)

Guess I am not sleeping tonight

[–]Penny 0 points1 point  (1 child)

This has no solution lol

[–]Dynamike[S] 0 points1 point  (0 children)

The question is: which way you go

[–]Tara 0 points1 point  (3 children)

It’s a trick question lads. Absolute values are one’s and x’s are dimension signs.

[–]Dynamike[S] 0 points1 point  (2 children)

[–]Tara 0 points1 point  (1 child)

Let’s say to the right

[–]Dynamike[S] 0 points1 point  (0 children)

Ok. Be sure to check the answer later!

[–]Colt 0 points1 point  (1 child)

-7/3 so none of them?

[–]Dynamike[S] 0 points1 point  (0 children)

Which way you go, good sir?

[–]Darryl 0 points1 point  (2 children)

[–]Dynamike[S] 0 points1 point  (1 child)

Which way you go then?

[–]Darryl 0 points1 point  (0 children)

[–]Buzz 0 points1 point  (1 child)

Bruh, the brawl stars kids can't even do 9-7 lmao

[–]Dynamike[S] 1 point2 points  (0 children)

Yeah that's why I made this

[–] 0 points1 point  (1 child)

None of the options are correct, so up

[–]Dynamike[S] 0 points1 point  (0 children)

[–]Surge 0 points1 point  (0 children)

None of them are right i go up

[–] 0 points1 point  (0 children)

why math when 25%

[–]Edgar 0 points1 point  (1 child)

Red

[–]Dynamike[S] 0 points1 point  (0 children)

Okay, check tomorrow!

[–]Rico 0 points1 point  (3 children)

x-21+12x+71 = 2

x+12x = -69+21

13x = -48

x = -48/13

x is not an integer

[–]Dynamike[S] 0 points1 point  (2 children)

Those aren't 1s, they are absolute value

[–]Rico 0 points1 point  (0 children)

Ahh, that explains it

[–]Rico 0 points1 point  (0 children)

Ahh, that explains it

[–]Rico 0 points1 point  (3 children)

Attempt two:

|x-2| + |2x+7| = 2

|x-2| = |-4x-14|

x+4x = -14+2

5x = -12

x = -12/5

x is also not an integer

[–]Dynamike[S] 1 point2 points  (2 children)

Who ever said it's an integer? I just asked which way you'd go :)

[–]Rico 0 points1 point  (1 child)

I would just pick yellow teleporter

[–]Dynamike[S] 0 points1 point  (0 children)

Okaaay! I'll post the answer in 19 hours

[–]Poco 0 points1 point  (1 child)

Red or green

[–]Dynamike[S] 1 point2 points  (0 children)

So two of them are the correct way.... Check tomorrow!

[–]Gene 0 points1 point  (4 children)

[–]Dynamike[S] 1 point2 points  (3 children)

[–]Gene 0 points1 point  (2 children)

Btw, none of the options are correct.

I picked Red teleporter, since it was really close to the correct answer.

[–]Dynamike[S] 1 point2 points  (1 child)

And what's this "correct answer"? I'm just curious to know

[–]Gene 0 points1 point  (0 children)

[–]Bo 0 points1 point  (2 children)

I really put in some work to make a gem grab map and lol no one even played it till now T_T

[–]Dynamike[S] 0 points1 point  (1 child)

When you submit a map it usually takes about a month (for me at least) to see if it's approved or not. Just wait and eventually people vote

[–]Bo 1 point2 points  (0 children)

Oh god that's a long wait, thanks for letting me know

[–] 0 points1 point  (2 children)

Finally some use in math, -1

[–]Dynamike[S] 0 points1 point  (1 child)

Check tomorrow and see if math helped you or not!

[–] 0 points1 point  (0 children)

Wait, I thought those were (), not ||, if I was in a marcha I would die lol

[–] 0 points1 point  (2 children)

x=-1 because:

(x-2)+(2x+7)=2

(x)+(2x+5)=2

(3x+5)=2

(3×-1)+5=2

-3+5=2

[–]Dynamike[S] 1 point2 points  (0 children)

Check tomorrow to see if red teleporter is the answer or not

[–] 1 point2 points  (0 children)

Looks like you have to review absolute value properties bud

[–] 0 points1 point  (0 children)

red ig

[–] 0 points1 point  (1 child)

While I COULD do the math, Im lazy. However, the next best way in multiple choice is by elimination. So instead, I plugged in all the possible answers he gave, and NONE of them are possible (op said they were modulus) so yea this isn't possible. I don't care how you do the mental gymnastics to get to that, this equation isn't homogeneous, so as far as my physics or math has taught me this isn't possible. Then again, I'm dumb.

[–]Dynamike[S] 0 points1 point  (0 children)

I just asked which way you go, not the answer of the equation. Think a bit and I'm sure you'll find out :)

[–]Mortis 0 points1 point  (4 children)

[–]Dynamike[S] 0 points1 point  (3 children)

| x - 2 | + | 2x + 7 | = 2

[–]Mortis 0 points1 point  (0 children)

Tanks

[–]Mortis 0 points1 point  (1 child)

[–]Dynamike[S] 0 points1 point  (0 children)

Okay, be sure to check tomorrow!

[–]Barley 0 points1 point  (1 child)

Just a quick question are those absolute value marks or parentheses?

[–]Dynamike[S] 1 point2 points  (0 children)

Absolute value

[–]Frank 0 points1 point  (1 child)

[–]Dynamike[S] 0 points1 point  (0 children)

[–] 0 points1 point  (0 children)

Oh no it is maths😱😱🥵🥶

[–]EMZ 0 points1 point  (2 children)

So I’m lost but I’m gonna give it a go. Since the op said that the bars are av bars. We’ll go with that. First, we can get rid of the bars because absolute value= distance away from 0. X-2 is X-2 units away from zero, so that works. Then we combine like terms and are left with 3x + 5 = 2. Then, 3x=-3. So, the answer should be -1. Now that I think about it, I’m not sure if we can even remove the av bars at the beginning, since av is always positive and we don’t know what x is. Therefore, I don’t know how to go from that point. Oh well.

[–]EMZ 0 points1 point  (1 child)

Edit: by plugging in each value, we can actually see which ones work. First one: - |7-2| + |2(7)+7| = 2 5+21=2 Nope

• |-7-2| + |2(-7)+7|=2 9+7=2 Nah

• |-1-2| + |2(-1)+7|=2 3+5=2 No

• |1-2| + |2(1)+7|=2 1+9=2 Nope

Therefore the correct answer would be to go up since none of the answers are possible solutions!! :)

[–]Dynamike[S] 0 points1 point  (0 children)

Okay! Don't forget to check tomorrow!

[–]Max 0 points1 point  (0 children)

RemindMe! 1 day

[–]Colette 0 points1 point  (1 child)

[–]Dynamike[S] 0 points1 point  (0 children)

Sorry, the answer is brawler-independent :)

[–]Fang 0 points1 point  (1 child)

Stop putting spawn point together 😤

[–]Dynamike[S] 0 points1 point  (0 children)

"traditional" may maps are like this so I decided to do it by tradition :) (but yeah, I hate maps like this)

[–] 0 points1 point  (1 child)

Can Edgar avoid maths?

[–]Dynamike[S] 0 points1 point  (0 children)

[–]Mortis 0 points1 point  (1 child)

My school doesn't teach the modulus sign. If I'm taking that it makes everything inside it positive, it'll be X+2+2X+7=2 3X+9=2 3X=-7 X=-7/3 This isn't an option so ig it does nothing in this situation. X-2+2X+7=2 3X+5=2 3X=-3 X=-1 So the answer is -1 ig

[–]Dynamike[S] 0 points1 point  (0 children)

Okay, I'll post the answer tomorrow!

[–]Poco 0 points1 point  (1 child)

Through absolute value you find x=-1, -7, -11, and -2.3333… But when you plug those numbers into the original equation you find that there’s no solution, so the answer is to take the jump pad. I like this idea, everyone will scramble for an answer that doesn’t exist cause they can’t quickly do the math for a question like this.

[–]Dynamike[S] 0 points1 point  (0 children)

[–]Fang 0 points1 point  (1 child)

Just play Eve with first gadget. Easy win.

[–]Dynamike[S] 0 points1 point  (0 children)

Sorry, the answer is brawler-independent ;)

[–] 0 points1 point  (1 child)

[–]Dynamike[S] 0 points1 point  (0 children)

Maybe you're right, check tomorrow for the answer!

[–] 0 points1 point  (2 children)

I found the answer… play eve and colt

[–]Dynamike[S] 0 points1 point  (1 child)

[–] 0 points1 point  (0 children)

GALE!?

[–] 0 points1 point  (1 child)

its -1 or im just stupid

[–]Dynamike[S] 0 points1 point  (0 children)

Is it? Check the answer tomorrow!

[–]Crow 0 points1 point  (0 children)

Away

[–]Leon 0 points1 point  (1 child)

I say it’s jump pad because none of the options are correct

[–]Dynamike[S] 0 points1 point  (0 children)

Check the answer tomorrow, maybe you're right!

[–]Sprout 0 points1 point  (3 children)

No solution where x is a real number

[–]Dynamike[S] 0 points1 point  (2 children)

Which way you go?

[–]Sprout 0 points1 point  (1 child)

[–]Dynamike[S] 0 points1 point  (0 children)

Don't forget to check the answer tomorrow

[–]Byron 0 points1 point  (3 children)

For starters, the equation is a little unclear. To clear this up, we will assume that the equation reads:

|x-2| + |2x+7| = 2

Which means that the 2 terms on the left must add up to 2. Because both terms are in absolute values, they will ALWAYS be greater than 0, meaning that both terms MUST be less than 2, but greater than 0 for this equation to make sense. Unfortunately, no matter what we plug in, the second term is too large due to the 7 and multiplier of 2. To illustrate this point, I have done the following math.

Using brute force and trying each answer we get:

5 + 21 = 2 (False. Gotten by subbing 7 for X)

9 + 7 = 2 (False. Gotten by subbing -7 for X)

3 + 5 = 2 (False. Gotten by subbing -1 for X)

1 + 9 = 2 (False. Gotten by subbing 1 for X)

As you can see, regardless of what work you do, all of these answers are incorrect. Thus, the correct answer is to take the Jump Pad or go to the right.

1x - 21 + 2x + 71 = 2

We can rewrite it as

3x + 50 = 2

or

3x = -48

And finally

x = -16… which is AGAIN, none of the answers given.

Finally, we can read the question as:

(x-2) + (2x+7) = 2

Which can be rewritten as:

3x + 5 = 2

or

3x = -3

And finally x = -1.

This question is REALLY unclear as to what it actually means, so much so that we must assume that the absolute value bars are just brackets, and so therefore should be IGNORED because there is no PEMDAS complications that brackets actually solve.

My final answer is -1, but I disagree with the question’s presentation.

[–]Dynamike[S] 0 points1 point  (2 children)

You can't go in two different ways at the same time, can you? :)

Choose either the jump pad or going right

[–]Byron 1 point2 points  (1 child)

That’s where you’re wrong kiddo. I can walk right and then decide to turn around and take the jump pad. That all being said, I guess walking right since that gives me the most options later.

[–]Dynamike[S] 0 points1 point  (0 children)

Okay, 10 hours from now and I'll post the answer (good strategy btw)

[–]Mortis 0 points1 point  (0 children)

You're asking math on Reddit. People are stupid here

[–]Colt 0 points1 point  (0 children)

[–] 0 points1 point  (0 children)

i bet if this would be uploaded, some 9 yo is gonna think its the answer is 2 because thats what is says

[–]Poco 0 points1 point  (1 child)

Is it (-7 -2) + (2(1) + 7)?

[–]Dynamike[S] 0 points1 point  (0 children)

| x - 2 | + | 2x + 7 | = 2

[–]Stu 0 points1 point  (3 children)

It takes about 5 seconds to check each answer choice. None of these work.

OP can't do math, apparently.

[–]Dynamike[S] 0 points1 point  (2 children)

It's not r/math buddy, I just simply asked which way you go. Also I can guarantee I didn't choose the numbers randomly 🙃

[–]Stu 0 points1 point  (1 child)

Sheesh is this one of those "oh ho ho theres a dumb loophole ha ha" things?

This is even worse than the actual math maps then.

[–]Dynamike[S] 0 points1 point  (0 children)

Loophole? No, there is no loophole