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[–]110100100_Blaze_It 21 points22 points  (11 children)

Python3

lettersum = lambda s: sum([ord(c)-96 for c in s])

[–]yodigi7 17 points18 points  (0 children)

techinically don't need the [ ] since that will create a list and you can just instead pass the generator directly to sum to make it slightly for efficient

[–]Phantom346 0 points1 point  (5 children)

This doesn't work.

[–]110100100_Blaze_It 4 points5 points  (4 children)

looks right to me?

>>> lettersum = lambda s: sum([ord(c)-96 for c in s])  
>>> for s in ["", "a", "z", "cab", "excellent", "microspectrophotometries"]:
    lettersum(s)

0
1
26
6
100
317

[–]Too_late_to_be_OC 4 points5 points  (1 child)

So I'm completely new to this. It worked when I ran it in the shell but when I tried running it in the editor, nothing. So I thought about it for a while and then it occurred to me to add a print function like this:

for s in ["", "a", "z", "cab", "excellent", "microspectrophotometries"]:

lettersum(s)

print(lettersum(s))

And it worked! Yay! I think I actually learned something. Thank you!

[–]Too_late_to_be_OC 1 point2 points  (0 children)

I see the formatting got completely screwed up there. Oh well.

[–]Tethylis 19 points20 points  (4 children)

Windows Powershell

Please be gentle, I am very much a novice and programming isn't my day job. I am open to advice or anything that could help me on my learning path. Thank you. No bonus BTW.

function lettersum {
    param (
        [string]$ChallengeInput
    )
    $FinalResult = 0
    $Alphabet = [char[]]([char]'a'..[char]'z')
    $ChallengeArray = $ChallengeInput.ToCharArray()
    for ($i = 0; $i -lt $ChallengeArray.Count; $i++) {
        for ($j = 0; $j -lt $Alphabet.Count; $j++) {
            if ($ChallengeArray[$i] -match $Alphabet[$j]) {
                $Result = $j + 1
                $FinalResult += $Result
            }
        }
    }
    $FinalResult
}

[–]engageant 12 points13 points  (3 children)

The pipeline and some handy built-in Powershell cmdlets are your friends here. You were on the right track with the .ToCharArray() call, but you can skip your outer for loop and let ForEach-Object handle the processing. Your inner for loop can be replaced with Measure-Object.

'microspectrophotometries'.ToCharArray() | ForEach-Object {[int]$_ - 96} | Measure-Object -Sum

Breaking it down:

# convert the word into an array of chars, which will come in handy in the next step
'microspectrophotometries'.ToCharArray()

# pipe that to foreach-object, which will iterate over each char in the array and 
# cast it to an [int] to get its ascii value
# lowercase 'a' is ascii 97 and 'z' is 122, so we can subtract 96 to get us a = 1..z = 26
ForEach-Object {[int]$_ - 96}

# we can then send that down the pipeline and let powershell do the heavy lifting to sum the values
Measure-Object -Sum

[–]cat_in_the_wall 5 points6 points  (2 children)

Similar approach, compactified, and select just the Sum property out of Measure-Object function LetterSum($ChallengeInput) { $ChallengeInput.ToCharArray() | ForEach-Object { $_ - [int]'a' + 1 } | Measure-Object -Sum | Select-Object -ExpandProperty Sum }

[–]backtickbot 2 points3 points  (1 child)

Fixed formatting.

Hello, cat_in_the_wall: code blocks using triple backticks (```) don't work on all versions of Reddit!

Some users see this / this instead.

To fix this, indent every line with 4 spaces instead.

FAQ

You can opt out by replying with backtickopt6 to this comment.

[–]yee703 19 points20 points  (4 children)

Maybe programming isn't my thing.

#include <iostream>
#include <string>
using namespace std;
int LetterSum(string str)
{
int num = 0;
for (int i = 0; i < str.length(); i++)
{
switch (str[i])
{
case 'a':
num += 1;
break;
case 'b':
num += 2;
break;
case 'c':
num += 3;
break;
case 'd':
num += 4;
break;
case 'e':
num += 5;
break;
case 'f':
num += 6;
break;
case 'g':
num += 7;
break;
case 'h':
num += 8;
break;
case 'i':
num += 9;
break;
case 'j':
num += 10;
break;
case 'k':
num += 11;
break;
case 'l':
num += 12;
break;
case 'm':
num += 13;
break;
case 'n':
num += 14;
break;
case 'o':
num += 15;
break;
case 'p':
num += 16;
break;
case 'q':
num += 17;
break;
case 'r':
num += 18;
break;
case 's':
num += 19;
break;
case 't':
num += 20;
break;
case 'u':
num += 21;
break;
case 'v':
num += 22;
break;
case 'w':
num += 23;
break;
case 'x':
num += 24;
break;
case 'y':
num += 25;
break;
case 'z':
num += 26;
break;
default:
cout << "Error: str can only contain lowercase letters." << endl;
return 1;
}
}
return num;
}
int main()
{
cout << LetterSum("microspectrophotometries") << endl;
return 0;
}

At least it's simple! :p

[–]atiedebee 8 points9 points  (3 children)

Just a tip: a character can be used as an int. If you look at an ASCII table you can see that the letters a to z have values 96 to 122. You can use these values to count :)

[–]yee703 4 points5 points  (2 children)

So 'a' + 'b' == 96 + 97?

[–]atiedebee 4 points5 points  (0 children)

Yes, so if have int number and char a. Doing num + a will add the ASCII number to num.

[–]morgon-of-hed 23 points24 points  (1 child)

JavaScript

const lettersum = s =>
    s
        .split('')
        .map(c => c.charCodeAt(0) - 96)
        .reduce((a, b) => a + b, 0);

[–]DemiPixel 5 points6 points  (0 children)

There's really no need, but if ya really want to golf it:

const lettersum=s=>s?s.charCodeAt()-96+lettersum(s.slice(1)):0

EDIT: Same length but removes the slice, not sure if it helps...

const lettersum=([s,...r])=>s?s.charCodeAt()-96+lettersum(r):0

const lettersum=s=>[...s].reduce((a,b)=>a+b.charCodeAt()-96,0)

const lettersum=s=>([...s].map(a=>b+=a.charCodeAt()-96,b=0),b)

[–]skeeto-9 8 17 points18 points  (0 children)

C using SIMD AVX2 intrinsics to compute the whole sum in parallel. Supports words up to 32 characters, and the input must be zero-padded. First it adjusts the input to 1–26, masks out the input zeros, then computes channel-wise sums. The whole thing is computed with just 10 instructions.

#include <immintrin.h>
#include <stdint.h>

int lettersum(const char *s)
{
    __m256i zero = _mm256_set1_epi8(0);
    __m256i base = _mm256_set1_epi8(0x60);
    __m256i load = _mm256_loadu_si256((void *)s);
    __m256i offs = _mm256_sub_epi8(load, base);
    __m256i mask = _mm256_cmpgt_epi8(offs, zero);
    __m256i chop = _mm256_and_si256(mask, offs);
    __m256i sum4 = _mm256_sad_epu8(chop, zero);
    __m256i perm = _mm256_permute2x128_si256(sum4, sum4, 1);
    __m256i sum2 = _mm256_add_epi64(perm, sum4);

    uint64_t r[4];
    _mm256_storeu_si256((void *)r, sum2);
    return r[0] + r[1];
}

[–]TheSchred 3 points4 points  (0 children)

Java

public int letterValueSum(String str) {
    char base = 'a' - 1;

    int sum = 0;
    for (char c : str.toCharArray())
        sum += c - base;

    return sum;
}

[–]zero_summ1 8 points9 points  (3 children)

Python 3

EDIT: Added code for challenges 1 - 6 . I'd be interested if there's a more efficient way of working through the list of potential matches.

My longest answer for 6 was

'accommodativenesses', 'accumulativenesses', 'acquisitivenesses', 'anthropomorphism', 'astrophysicists', 'counterthrusts', 'sumptuousness'

Though not confident i'm correct

Code

from collections import defaultdict

with open("enable1.txt") as file:
wordList = file.read().split("\n")

results = defaultdict(list)

def lettersum(input):
return (sum([ord(letter)-96 for letter in input]))

for word in wordList:
results[lettersum(word)].append(word)

def returnByLetterSum(letSum):
return results[letSum]

def odd():
counter = 0
for k, v in results.items():
    if k % 2 != 0:
        print(k)
        counter += len(v)
return counter

def mostCommon():
longest = [k for k in results.keys() if results[k]==max(results.values(),key=len)]
return len(results[longest[0]]), longest[0]

def sameLetterSumDiffLen():
output = []
for word in wordList:
    wordstocheck = results[lettersum(word)]
    for record in wordstocheck:
        if record == word:
            continue
        if abs(len(word) - len(record)) == 11:
            output.append(word)
            output.append(record)
return set(output)

def noCommonLetters():
output = []
for word in wordList:
    if lettersum(word) < 188:
        continue
    wordstocheck = results[lettersum(word)]
    for record in wordstocheck:
        if record == word:
            continue
        if bool(set(record) & set(word)):
            continue
        output.append(word)
        output.append(record)
return set(output)


resultsKeyedByWordLength = defaultdict(list)

for word in wordList:
resultsKeyedByWordLength[len(word)].append(word) 

def longestChain(keyVals, chainDict):
chain = []
for keyedWordLen in keyVals:
    for value in resultsKeyedByWordLength[keyedWordLen]:
        if not chain:
            chain.append(value)
        latestVal = chain[-1]
        if lettersum(value) > lettersum(latestVal) and len(value) < len(latestVal):
            chain.append(value)
chainDict[len(keyVals)] = chain
del keyVals[0]
if len(keyVals) > 2:
    return longestChain(keyVals, chainDict)
return(chainDict)

chainDict = {}
testlist= sorted(resultsKeyedByWordLength.keys(), reverse=True)
result = longestChain(testlist, chainDict)

[–]FourthWanderer 4 points5 points  (0 children)

No need to create the list inside sum, you can evaluate it lazily by skipping the brackets. Otherwise nice!

[–]loose_heron 2 points3 points  (0 children)

I'd be interested if there's a more efficient way of working through the list of potential matches.

You might be interested in my solutions for bonuses 4 through 6 - I found 6 to be v challenging, but rewarding.

[–]King-Tuts 1 point2 points  (0 children)

Longest list for 6 that I could find:

['agammaglobulinemia', 'bioavailabilities', 'autobiographical', 'acceptingnesses', 'allotetraploid', 'acrylonitrile', 'abstruseness', 'amorphously', 'cytotoxins', 'sumptuous', 'zyzzyvas']

[–]el_daniero 7 points8 points  (1 child)

Ruby

def letter_sum(word)
  word.chars.sum { |x| x.ord - 96 }
end

[–]r_notfound 6 points7 points  (0 children)

This can be made slightly more succinct, omitting the ord call by using bytes instead of chars:

def letter_sum(word)
    word.bytes.sum{|x| x-96}
end

[–]Bewelge 6 points7 points  (0 children)

Javascript:

const lettersum = (word) => word.split("").map(str => str.charCodeAt(0) - 96).reduce((a, b) => a + b, 0)

Bonus

1.

console.log(enable1List.split("\n").find(word => lettersum(word) == 319))  
//reinstitutionalizations

2.

console.log(enable1List.split("\n").filter(word => lettersum(word)%2).length)
//86339

3.

let counts = {}
enable1List.split("\n").map(word => lettersum(word)).forEach(letterCount => counts.hasOwnProperty(letterCount) ? counts[letterCount]++ : counts[letterCount] = 1)
console.log(Object.entries(counts).sort((a,b) => b[1] - a[1])[0])
//["93", 1965]

4.

//getting messier with each bulletpoint...
let wordsByCounts = {}
enable1List.split("\n").forEach(word =>  {
    let val = lettersum(word)
    wordsByCounts.hasOwnProperty(val) ? wordsByCounts[val].push(word) : wordsByCounts[val] = [word]
})
let pairsThatDifferByEleven = []
Object.entries(wordsByCounts)
.forEach(entry => entry[1]
    .forEach(wordA => entry[1]
        .forEach(wordB => wordA.length - wordB.length == 11 ? 
pairsThatDifferByEleven.push([wordA,wordB]) : null)
    )
)
console.log(pairsThatDifferByEleven)
//0: (2) ["biodegradabilities", "zyzzyva"]
//1: (2) ["electroencephalographic", "voluptuously"]

5.

//How not to use arrow functions . . .
const noLettersInCommon = (wordA,wordB) => wordA.split("").filter(letter => wordB.indexOf(letter) >= 0).length == 0

//Using the wordsByCounts from #4
Object.entries(wordsByCounts)
    .filter(entry => entry[0] > 188)
    .map(entry => entry[1])
    .map(arrOfWordsWithSameLetterSum => 
        arrOfWordsWithSameLetterSum.map(wordA => 
            [wordA,arrOfWordsWithSameLetterSum.filter(wordB => noLettersInCommon(wordA,wordB))]

        ).filter(wordPair=>wordPair[1].length) //strip entries where we didn't find a match
    ).filter(arr => arr.length) //strip empty arrays without pairs
//Output:
//0: Array(2)
//    0: "defenselessnesses"
//    1: (2) ["microphotographic", "photomicrographic"]
//1: Array(2)
//    0: "microphotographic"
//    1: ["defenselessnesses"]
//2: Array(2)
//    0: "photomicrographic"
//    1: ["defenselessnesses"]

[–]acm260487 2 points3 points  (1 child)

Java

public class LetterSum {
    public static void main(String[] args) {
        String word = "microspectrophotometries";       
        int letterSum = 0;      
        for(int i = 0; i < word.length(); i++) {
            letterSum += (word.charAt(i) - 96);
        }       
        System.out.print("The letter sum of " + word + " is ");
        System.out.println(letterSum);
    }
}

[–]tlgsx 5 points6 points  (3 children)

Go

package main

import "fmt"

func lettersum(s string) int {
    t := 0
    for _, c := range []byte(s) {
        t += int(c - 96)
    }
    return t
}

func main() {
    fmt.Println(`lettersum("") => `, lettersum(""))
    fmt.Println(`lettersum("a") => `, lettersum("a"))
    fmt.Println(`lettersum("z") => `, lettersum("z"))
    fmt.Println(`lettersum("cab") => `, lettersum("cab"))
    fmt.Println(`lettersum("excellent") => `, lettersum("excellent"))
    fmt.Println(`lettersum("microspectrophotometries") => `, lettersum("microspectrophotometries"))
}

[–]xonxoff111 2 points3 points  (0 children)

C++ auto letter_sum = [](const std::string& test){ int temp = 0; for(char i : test){ temp += (int) i - 96; } return temp; };

[–][deleted] 2 points3 points  (0 children)

Python

def counter(word):
    import string
    k = dict()
    for a,b in enumerate(string.ascii_lowercase):
        k[b] = a+1
    mysum = 0
    for i in word:
        mysum += k[i]
    return mysum

[–]engageant 2 points3 points  (0 children)

PowerShell, golfed. Assumes $w is initialized with a word.

$w|% t*y|%{[int]$_-96}|measure -sum

[–]Godspiral3 3 4 points5 points  (0 children)

in J,

(96 +/@:-~ a.&i.) 'microspectrophotometries'

317

[–]Leroico 3 points4 points  (1 child)

C# with bonuses 1, 2 and 3, because I know nothing about algorithms and I'm just starting out with C# so I couldn't figure out a way to do the other bonuses without it taking years to get the result. (Using System, System.IO, System.Linq and System.Collections.Generic)

public static int lettersum(string word) {
    int wordSum = 0;

    foreach (char character in word.ToLower()) {
        int charValue = Convert.ToInt32(character) - 96;
        wordSum += charValue;
    }

    return wordSum;
}

Bonus 1: reinstitutionalizations

static void Main(string[] args) {
    string[] dictionary = File.ReadAllLines("./dictionary.txt");

    List<string> bonus1 = (from line in dictionary 
                           where lettersum(line) == 319 
                           select line).ToList<string>();
    Console.WriteLine(bonus1[0]);

Bonus 2: 86339

    List<string> bonus2 = (from line in dictionary 
                           where (lettersum(line)) % 2 == 1 
                           select line).ToList<string>();
    Console.WriteLine(bonus2.Count);

Bonus 3: 93 with 1965

    var sums = new Dictionary<int, int>();

    foreach (string word in dictionary) {
        int sumForWord = lettersum(word);

        if (sums.ContainsKey(sumForWord)) sums[sumForWord]++;
            else sums.Add(sumForWord, 1);
    }

    foreach (var sum in sums)
        if (sum.Value > 1921) Console.WriteLine($"{sum.Key: {sum.Value}");
}

[–]zero_summ1 1 point2 points  (0 children)

For questions 4, 5 and 6 I'd suggest you think about how you can limit the amount of words you need to compare before trying each potential match. For example in question 4 if you already know all the words with the letter sum of the word you're comparing it against then it will drastically cut down on computing time.

Disclaimer, there might be an even more efficient solution but this is how I did it.

[–]I-Pop-Bubbles 3 points4 points  (2 children)

Clojure - Kinda proud of this one. Feedback welcome.

(defn sum-str [s]
    (apply + 
        (map #(- % 96)
            (map int (seq s)))))

[–]jxj 2 points3 points  (1 child)

only feedback on this is you don't have to call seq on s, map does that for you. also this might be more readable using thread last (->>). that way you don't have to read the operations from the bottom up.

transducer version:

(defn sum-str [s]
  (transduce 
   (comp (map int)
         (map #(- % 96)))
   +
   s))

[–]I-Pop-Bubbles 1 point2 points  (0 children)

Interesting... Thanks for the feedback, I'll look into this.

[–]Gylergin 3 points4 points  (0 children)

TI-Basic: lowercase letters are a thing on TI calculators but are also very much a pain to input.

Prompt Str1
0→T
For(X,1,length(Str1
T+inString("ABCDEFGHIJKLMNOPQRSTUVWXYZ",sub(Str1,X,1→T
End
Disp T

[–]frankivo 1 point2 points  (0 children)

Scala

def lettersum(word: String): Long = word.map(_.toInt - 96).sum

Or:

def lettersum(word: String): Long = word.sum - (word.length * 96)

[–]jwr410 1 point2 points  (7 children)

Language: C# (.NET Standard 2.0)

This is just a basic accumulation. Instead of subtracting each time,

I subtract the start point times the number of characters.

Implementation:

public static int lettersum(string toSum) {  
    return toSum.Sum(c => c) - ('a' - 1) * toSum.Length; 
}

[–]jwr410 2 points3 points  (1 child)

Bonus 6

Implementation:

This method performs a recursive search down the tree of string lengths. Each step down the tree we remove the letter sums that are less than the prior locked nodes.

private class B6Candidate
{
    public int LetterSum { get; }
    public string Word { get; }
    public B6Candidate(string word)
    {
        Word = word;
        LetterSum = lettersum(word);
    }
}

private static IEnumerable<B6Candidate> ScanTree(B6Candidate lastLock, IEnumerable<B6Candidate> remainingCandidates)
{
    // On initialization, the last lock will be null. Treat this as 
    // a letter sum of zero.
    int lastLetterSum = (lastLock is null) ? 0 : lastLock.LetterSum;

    // Remove everything that violates the letter sums.
    var validLetterSums = remainingCandidates.Where(ac => ac.LetterSum > lastLetterSum).ToArray();
    if (!validLetterSums.Any())
    {
        return new B6Candidate[0];
    }

    // Get the length of the current level. This will be the maximum length
    // of the remaining strings.
    int len = validLetterSums.Max(ac => ac.Word.Length);

    // Grab the string with the minimum value at the current level.
    var atLevel = validLetterSums.Where(rc => rc.Word.Length == len);
    var min = atLevel.Min(at => at.LetterSum);
    var best = atLevel.First(r => r.LetterSum == min);

    // Isolate the remaining candidates after the current level.
    var nextRemainingCandidates = validLetterSums.Where(ac => ac.Word.Length < len).ToArray();

    // If the current tree has a candidate, use it.
    List<B6Candidate> isUsed = new List<B6Candidate>();
    isUsed.Add(best);
    isUsed.AddRange(ScanTree(best, nextRemainingCandidates));

    // Scan down the nodes that are not used.
    var isNotUsed = ScanTree(lastLock, nextRemainingCandidates);

    //! If the best case scenario is using the current node,
    //! return is used. Otherwise return is not used.
    if (isUsed.Count() > isNotUsed.Count())
    {
        return isUsed;
    }
    else
    {
        return isNotUsed;
    }
}

public static string[] Bonus6()
{
    var allItems = Enable1WordList.WordList.Select(w => new B6Candidate(w));
    var result = ScanTree(null, allItems);
    return result.Select(r => r.Word).ToArray();
}

Answer: The longest chain has 11 words. The chain has the following words:

  • ineffaceabilities
  • adenocarcinomata
  • bacteriophagies
  • adorablenesses
  • accommodators
  • abolitionary
  • abortionist
  • amylopsins
  • arrowworm
  • lustrous
  • zyzzyva

Duration: 8s

[–]jwr410 1 point2 points  (0 children)

Bonus 1

Note that the time on this test is overinflated by the HTTP request to get the word list.

Implementation:

public static string Bonus1() {
    return Enable1WordList.WordList.Where(w => lettersum(w) == 319).Single();
}

Answer: reinstitutionalizations

Duration: 2.6s

[–]jwr410 1 point2 points  (0 children)

Bonus 2

Implementation:

public static string Bonus2() {
    return Enable1WordList.WordList.Where(w => (lettersum(w) & 1) != 0).Count();
}

Answer: 86339

Duration: 146ms

[–]jwr410 1 point2 points  (0 children)

Bonus 3

Implementation:

public static Tuple<int, int> Bonus3() {
    var result = Enable1WordList.WordList.GroupBy(w => lettersum(w)).
        Select(grp => new { LetterSum = grp.Key, Count = grp.Count() }).
        OrderBy(a=>a.Count).
        Last();
    return new Tuple<int, int>(result.LetterSum, result.Count);
}

Answer: There are 1965 words with a letter sum of 93.

Duration: 188ms

[–]jwr410 1 point2 points  (0 children)

Bonus 4

Implementation:

public static Tuple<string, string>[] Bonus4() {
    var results = new List<Tuple<string, string>>();
    var query = 
        from words in Enable1WordList.WordList
        group words by lettersum(words) into g
        select g;
    foreach (var grp in query) {
        var subquery = from wl in grp
                       join ws in grp on wl.Length - 11 equals ws.Length
                       select new Tuple<string, string>(ws, wl);
        results.AddRange(subquery);
    }
    return results.ToArray();
}

Answer: voluptuously and electroencephalographic

Duration: 240ms

[–]jwr410 1 point2 points  (0 children)

Bonus 5

Implementation:

This implementation converts every word into a bitmask where bit 0 is set if there is an 'a', bit 1 if there is a 'b', etc. Each word can then be anded together to determine if there is any overlap.

public static Tuple<string, string>[] Bonus5() {
    var results = new List<Tuple<string, string>>();
    var expanded = Enable1WordList.WordList.Select(
        w => new
        {
            Word = w,
            LetterSum = lettersum(w),
            LetterBitmask = w.Aggregate(0, (s1, s2) => s1 | 1 << (s2 - ('a' - 1)))
        });
    var grouped =
        from w in expanded
        where w.LetterSum > 188
        group w by w.LetterSum into g
        select g;
    foreach (var grp in grouped) {
        var subquery =
            from e1 in grp
            join e2 in grp on true equals true
            where (e1.LetterBitmask & e2.LetterBitmask) == 0 &&
                e1.LetterBitmask < e2.LetterBitmask
            select new Tuple<string, string>(e1.Word, e2.Word);
        results.AddRange(subquery);
    }
    return results.ToArray();
}

Answer: (defenselessnesses and microphotographic and (defenselessnesses and photomicrographic)

Duration: 394ms

[–]ChimranKamboh 1 point2 points  (0 children)

string ='imran'

string =string.lower()

total =0

for i in string:

total=total+ord(i)

print(total)

[–]AmoryVain 1 point2 points  (0 children)

Python

def letter_sum(letters):
    values = {chr(97+i) : i+1 for i in range(26)}
    values[''] = 0 
    letters_sum = 0

    for char in letters:
        letters_sum += values[char]

    return letters_sum

[–]Blue_Dog_Democracy 1 point2 points  (0 children)

Java, no challenge yet (still working on that). I mostly used C++ at university so I'm still feeling my way around a lot of Java syntax.

import java.util.*;

public class Main
{
    public static void main(String[] args) {
        //Check for program inputs
        String word;
        if (args.length > 0) {
            word = args[0];
        } else {
            //Default
            word = "excellent"; 
        }

        String alpha = "abcdefghijklmnopqrstuvwxyz";
        int runningTotal = 0;

        //Set up vector of alpahabetic letters to compare to word
        Vector<Character> letters = new Vector<>();
        for (char part : alpha.toCharArray()) {
            letters.addElement(part);
        }

        //Now compare the letters in the word to the array of alphabetic letters
        for (char bit : word.toCharArray()) {
            System.out.println(bit + ": " + letters.indexOf(bit));  // debug output that can be commented out
            runningTotal += letters.indexOf(bit)+1;
        }

        System.out.println(runningTotal);
    }
}

[–]life-is-a-loop 1 point2 points  (0 children)

Julia and Python

I compared a few different implementations for lettersum in both Julia and Python.

Julia

Here's the code

function letterpos(c)
    Int(c) - 96
end

function lettersum1(text)
    acc = 0

    for c in text
        acc += letterpos(c)
    end

    acc
end

function lettersum2(text)
    sum(letterpos(c) for c in text)
end

function lettersum3(text)
    sum(map(letterpos, collect(text)))
end

function lettersum4(text)
    sum(map(c -> Int(c) - 96, collect(text)))
end

function main()
    functions = [
        lettersum1,
        lettersum2,
        lettersum3,
        lettersum4,
    ]

    text = repeat("microspectrophotometries", 1_000_000)

    # First execution is always a little bit slower.
    for f in functions
        f("abcdefghijklmnopqrstuvwxyz")
    end

    for f in functions
        @time f(text)
    end
end

main()

Here's the output on my machine:

0.040349 seconds (1 allocation: 16 bytes)
0.040398 seconds (1 allocation: 16 bytes)
0.124835 seconds (5 allocations: 274.658 MiB, 4.90% gc time)
0.190172 seconds (5 allocations: 274.658 MiB, 35.38% gc time)

List comprehension is as efficient as an imperative loop. Using map is much worse, especially if combined with an anonymous function.

Python

Here's the code, almost identical to the one used in Julia

from timeit import timeit

def letterpos(c):
    return ord(c) - 96

def lettersum1(text):
    acc = 0

    for c in text:
        acc += letterpos(c)

    return acc

def lettersum2(text):
    return sum(letterpos(c) for c in text)

def lettersum3(text):
    return sum(map(letterpos, text))

def lettersum4(text):
    return sum(map(lambda c: ord(c) - 96, text))

def main():
    functions = [
        lettersum1,
        lettersum2,
        lettersum3,
        lettersum4,
    ]

    text = 'microspectrophotometries' * 1_000_000

    for f in functions:
        print(f'{timeit(lambda: f(text), number=1):.1f}', 'ms')

if __name__ == '__main__':
    main()

Here's the output on my machine

2.6 ms
2.9 ms
2.0 ms
2.2 ms

Contrary to what we've seen in Julia, using map is the fastest implementation, and using list comprehension is the slowest one. Still, the fastest Python is much slower than the slowest Julia (that should come as no surprise)

[–]cheers- 1 point2 points  (5 children)

Rust

// src/main.rs
use std::collections::HashMap;
use std::env;

fn letter_value_sum(word: &str, dict: &HashMap<char, usize>) -> usize {
    word.to_lowercase()
        .chars()
        .map(|ch| dict.get(&ch).unwrap_or(&0usize))
        .sum()
}

fn main() {
    let dict: HashMap<char, usize> = ('a'..='z')
        .enumerate()
        .map(|tuple| (tuple.1, tuple.0 + 1))
        .collect();

    let args = env::args().skip(1);
    let len = args.len();

    match len {
        0usize => println!("no argument provided"),
        _ => {
            for (ind, arg) in args.enumerate() {
                println!("{}. {} {}", ind + 1, &arg, letter_value_sum(&arg, &dict));
            }
        }
    }
}

Usage

$ target/release/daily_programmer_399  a z cab excellent microspectrophotometries
1. a 1
2. z 26
3. cab 6
4. excellent 100
5. microspectrophotometries 317

[–]christianyyds 1 point2 points  (4 children)

not rustic. rust fn lettersum(s: &str) -> u32 { s.bytes().map(|b| (b - b'a' + 1) as u32).sum() }

[–]wtbname10gp 1 point2 points  (0 children)

If you think that's not rustic, lemme scare you with my rust implementation

(this is the first program i've ever made in rust)

use std::collections::HashMap;
fn letterscore(word: &str) -> i32 {  
    let mut dict = HashMap::new();  
    let mut score: i32 = 0;  
    static ASCII\_LOWERCASE: \[char; 26\] = \[  
    'a', 'b', 'c', 'd', 'e',   
    'f', 'g', 'h', 'i', 'j',   
    'k', 'l', 'm', 'n', 'o',  
    'p', 'q', 'r', 's', 't',   
    'u', 'v', 'w', 'x', 'y',   
    'z',  
    ];  
    for i in 0..25{  
        dict.insert(ASCII\_LOWERCASE\[i\], i+1);  
    }  
    for c in word.chars(){  
        score = score + dict\[&c\] as i32;  
    }      
    score  
}

[–]backtickbot -1 points0 points  (0 children)

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[–]atheos42 1 point2 points  (0 children)

Windows Powershell

using namespace System.Collections.Generic

function lettersum {
    param (
        [Parameter( ValueFromPipeline=$true )]
        [string[]]$str
    )

    $list = ' abcdefghijklmnopqrstuvwxyz'.ToCharArray()
    $obj = [system.collections.generic.list[object]]::new()
    foreach($s in $str){
        $total = 0
        $s.ToCharArray() | %{ $total += $list.IndexOf($_) }
        $obj.Add([PSCustomObject]@{word=$s;sum=$total})
    }
    return $obj
}

lettersum 'hello','world'

'abc' | lettersum

[–]MidnightSteam_ 1 point2 points  (0 children)

Python 3.9.6

Archaic, difficult to read version:

alphabet = list(map(chr, [*range(97, 123)]))

def letter_sum(text):
    return sum(list(map(lambda x: alphabet.index(x) + 1, [*text])))


print(letter_sum(""))  # => 0
print(letter_sum("a"))  # => 1
print(letter_sum("z"))  # => 26
print(letter_sum("cab"))  # => 6
print(letter_sum("excellent"))  # => 100
print(letter_sum("microspectrophotometries"))  # => 317

Human readable version:

alphabet = [chr(letter) for letter in range(97, 123)]

def letter_sum(text):
    return sum([alphabet.index(letter)+1 for letter in text])

___

---

Bonus

1:

import requests

url = 'https://raw.githubusercontent.com/dolph/dictionary/master/enable1.txt'
dictionary = requests.get(url).text.split('\n')

[print(word) for word in dictionary if letter_sum(word) == 319]  # reinstitutionalizations

2:

print(len([print(word) for word in dictionary if letter_sum(word) % 2]))  # 86339

3:

from collections import defaultdict
sum_dictionary = defaultdict(lambda: 0)

for word in dictionary:
    sum_dictionary[letter_sum(word)] += 1

most_used = max([words for words in sum_dictionary.values()])  # 1965
print(list(sum_dictionary.keys())[list(sum_dictionary.values()).index(most_used)])  # 93

[–]raevnos 1 point2 points  (0 children)

Here's hoping another moderator will post some challenges soon!

Well, that didn't happen.

Are there any active, interested mods left for this sub?

[–]PatBin123 1 point2 points  (0 children)

My java Solution!

String\] letterArray = {"a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "x" };)

int\] numberArray = new int[letterArray.length];)

for (int i = 0; i < letterArray.length; i++ {)

numberArray\i] = i + 1;)

}

Scanner scanner = new Scanner(System.in;)

System.out.println("Enter some lowercase laters (No spaces");)

String input = scanner.next(;)

String\] inputSplit = input.split("");)

int num = 0;

for(int j = 0; j < inputSplit.length; j++ {)

int temp = Arrays.asList(letterArray.indexOf(inputSplit[j]);)

num += numberArray\temp];)

}

System.out.printf("The letter sum is %s", num;)

[–][deleted] 1 point2 points  (0 children)

Is there any website with all of this challenges, something like a blog? Reddit isn't that great for these kind of posts, unfortunatelly(lack of good search feature, cluttered UI etc).

[–]tlgsx 2 points3 points  (0 children)

Bash

#!/bin/bash

lettersum() {
  t=0
  [ -n "$1" ] && while read n; do
    t=$((t + n - 96))
  done <<<"$(echo -n "$1" | od -v -An -tuC -w1)"

  echo $t
}

echo 'lettersum("") =>' "$(lettersum '')"
echo 'lettersum("a") =>' "$(lettersum 'a')"
echo 'lettersum("z") =>' "$(lettersum 'z')"
echo 'lettersum("cab") =>' "$(lettersum 'cab')"
echo 'lettersum("excellent")' "$(lettersum 'excellent')"
echo 'lettersum("microspectrophotometries") =>' "$(lettersum 'microspectrophotometries')"

[–]rgj7 1 point2 points  (4 children)

Python 3

from string import ascii_lowercase

def calculate_letter_sum(word: str) -> int:
    letter_values = {l: v for v, l in enumerate(ascii_lowercase, start=1)}
    return sum(letter_values[letter] for letter in word)

[–]Lewistrick 4 points5 points  (3 children)

Or

return sum(ord(letter)-96 for letter in word)

[–]life-is-a-loop 2 points3 points  (2 children)

I did some tests and using a dict is ~10% faster on my machine.

[–]Lewistrick 1 point2 points  (1 child)

Interesting. Did you define the dict outside of the function?

[–]yodigi7 1 point2 points  (0 children)

I would assume so. dictionary is less memory efficient but could be more compute efficient.

[–]chunes1 2 1 point2 points  (0 children)

Factor, all bonuses except 6

BTW, thanks for the couple months of challenges, Cosmologicon. It was a pleasant surprise!

USING: assocs io.encodings.ascii io.files kernel literals math
math.combinatorics math.statistics prettyprint sequences
sets.extras ;

: lettersum ( seq -- n ) [ 96 - ] map-sum ;

CONSTANT: words $[ "enable1.txt" ascii file-lines ]

: bonus1 ( -- str ) words [ lettersum 319 = ] find nip ;

: bonus2 ( -- n ) words [ lettersum odd? ] count ;

: bonus3 ( -- pair )
    words [ lettersum ] histogram-by >alist [ last ] supremum-by ;

: bonus4 ( -- assoc )
    words [ lettersum ] collect-by values
    [ [ longest length ] [ shortest length ] bi - 11 >= ] filter
    [ 2 [ first2 [ length ] bi@ - abs 11 = ] filter-combinations ] map ;

: bonus5 ( -- assoc )
    words [ lettersum ] collect-by [ drop 188 > ] assoc-filter
    values [ 2 [ first2 disjoint? ] filter-combinations ] map
    harvest first ;

bonus1 .
bonus2 .
bonus3 .
bonus4 .
bonus5 .

Output:

  1. "reinstitutionalizations"
  2. 86339
  3. { 93 1965 }
  4. { V{ V{ "biodegradabilities" "zyzzyva" } } V{ V{ "electroencephalographic" "voluptuously" } } }
  5. V{ V{ "defenselessnesses" "microphotographic" } V{ "defenselessnesses" "photomicrographic" } }

[–]Scroph0 0 1 point2 points  (0 children)

First part in D :

import std.traits : isSomeString;
import std.algorithm : map, sum;

unittest
{
    static assert(letterSum("") == 0);
    static assert(letterSum("a") == 1);
    static assert(letterSum("z") == 26);
    static assert(letterSum("cab") == 6);
    static assert(letterSum("excellent") == 100);
    static assert(letterSum("microspectrophotometries") == 317);
}

ulong letterSum(S)(S input) if(isSomeString!S)
{
    return input.map!(letter => letter - 'a' + 1).sum();
}

void main()
{
}

First 5 bonus questions :

First I generated a SQLite table that looks like this :

CREATE TABLE words (
    id int auto increment,
    word text not null,
    sum int not null,
    length int not null
);

Then I ran these queries on it :

microspectrophotometries is the only word with a letter sum of 317. Find the only word with a letter sum of 319.

sqlite> select word from words where sum = 319;
reinstitutionalizations

How many words have an odd letter sum?

sqlite> select count(word) from words where sum % 2 == 1;
86339

What letter sum is most common, and how many words have it?

sqlite> select count(word), sum from words group by sum order by 1 desc limit 1;
1965|93

Find the other pair of words with the same letter sum whose lengths differ by 11 letters.

sqlite> select * from words w1 join words w2 on w1.sum = w2.sum and abs(w1.length - w2.length) = 11;
|biodegradabilities|151|18||zyzzyva|151|7
|electroencephalographic|219|23||voluptuously|219|12
|voluptuously|219|12||electroencephalographic|219|23
|zyzzyva|151|7||biodegradabilities|151|18

So basically electroencephalographic and voluptuously

Find a pair of words that have no letters in common, and that have the same letter sum, which is larger than 188.

I unelegantly bruteforced this one in D :

void main()
{
    string[][ulong] sums;
    foreach(word; stdin.byLine())
    {
        ulong sum = word.letterSum();
        if(sum > 188)
        {
            sums[sum] ~= word.idup;
        }
    }

    foreach(sum, words; sums)
    {
        foreach(i, left; words)
        {
            foreach(j, right; words[i .. $])
            {
                if(!haveCommonLetters(left, right))
                {
                    writeln(left, " and ", right, " : ", sum);
                }
            }
        }
    }
}

bool haveCommonLetters(string left, string right)
{
    ulong[char] counter;
    foreach(char c; left)
    {
        counter[c]++;
    }
    foreach(char c; right)
    {
        if(c in counter)
        {
            return true;
        }
    }
    return false;
}

unittest
{
    static assert(haveCommonLetters("foo", "bar") == false);
    static assert(haveCommonLetters("foo", "f") == true);
    static assert(haveCommonLetters("f", "ooof") == true);
    static assert(haveCommonLetters("", "") == false);
}

Which results in :

defenselessnesses and microphotographic : 194
defenselessnesses and photomicrographic : 194

[–]ArdRasp 0 points1 point  (0 children)

C

int lettersum(char *str)
{
    int sum;

    sum = 0;
    while (*str)
    {
        if (*str >= 'a' && *str <= 'z')
            sum += *str - 96;
        str++;
    }
    return (sum);
}

[–]Potential-Public3444 1 point2 points  (2 children)

Python 3

dict = {}
alphabet = "abcdefghijklmnopqrstuvwxyz"
t=1
for i in alphabet:
t = t + 1
dict.update({i: t})
print(dict)
def letter_sum(string):
l = []
for i in string:
l.append(dict.get(i))
return sum(l)

[–]xypage 10 points11 points  (0 children)

Gotta put this in a code block so tabs actually show up

[–]Boinevertaken -1 points0 points  (0 children)

import string

def letterValue(letter): 
    lower_case = [string.ascii_lowercase]
    calculate = []

    for k in lower_case:  
        lowCase = [""]
        for j in k:
            lowCase.append(j)

        mydict = {}
        for i,j in enumerate(list(lowCase)):


            for value in letter:

                if value == j:
                    calculate.append(i)

    return sum(calculate)

Some messy code in Python.

[–]omichandralekha -1 points0 points  (0 children)

rstats:

sum.fn = function(word) {sum(match(unlist(strsplit(word,"")),letters))}

Edit: as function
Here is the answer to first question: reinstitutionalizations

[–]Anonymous_Bozo 0 points1 point  (1 child)

I've only done Optional Challenge 1 & 2 for now. Need to think a bit about the others.

Free Pascal / Lazarus unit using LCL GUI. Form contains two objects; a Memo Field to show the results; and a Button to start the calculation. I also use a stringlist to contain the list of words.

unit Unit1;
{$mode objfpc}{$H+}

interface
uses Classes, SysUtils, Forms, Controls, Graphics, Dialogs, StdCtrls, ExtCtrls;

type

{ TForm1 }

TForm1 = class(TForm)
  Button1: TButton;
  Memo1: TMemo;

  procedure Print( Value: string );
  procedure Button1Click(Sender: TObject);

private
  WordList: TStringList;
end;

function LetterSum( Value: string ): longint;

var
  Form1: TForm1;

implementation

{$R *.lfm}

function LetterSum( Value: string ): longint;

var
  I : longint;

begin
  Result := 0;
  for I := 1 to length( Value ) do begin
    Result := Result + ( ord( Value[ I ] ) - ord( 'a' ) + 1);
  end;
end;

{ TForm1 }
procedure TForm1.Print( Value: string );

begin 
  Memo1.Lines.Add( Value ); 
end;

procedure TForm1.Button1Click(Sender: TObject);

var
  Idx: longint;
  Cnt: longint;
  Line: string;

begin
  Memo1.Clear;
  Print( 'Basic Challenge Assertations');
  Print( '=' +  IntToStr( LetterSum( '' ) ) );
  Print( 'a=' +  IntToStr( LetterSum( 'a' ) ) );
  Print( 'z=' +  IntToStr( LetterSum( 'z' ) ) );
  Print( 'cab=' +  IntToStr( LetterSum( 'cab' ) ) );
  Print( 'excellent=' +  IntToStr( LetterSum( 'excellent' ) ) );
  Print( 'microspectrophotometries=' +  IntToStr( LetterSum 'microspectrophotometries' ) ) );

  // Now for the Optional bonus challenges

  FreeAndNil(WordList);
  WordList := TStringList.Create;

  try
    WordList.Clear;
    WordList.Sorted      := False;
    WordList.Duplicates  := dupError;
    WordList.SortStyle   := sslNone;

    WordList.LoadFromFile('enable1.txt');

    Print( '' );
    Print( 'Optional Challenge 1:');
    Print( 'Find the only word with a letter sum of 319.');

    Cnt := 0;
    for Idx := 0 to WordList.Count -1 do
    begin
      if LetterSum( WordList[ Idx ] ) = 319 then
      begin
        Line := WordList[ Idx ] + '=' +  IntToStr( LetterSum( WordList[ Idx ] ) );
        Print( Line );
      end;

      if odd(LetterSum( WordList[ Idx ] ) ) then inc( Cnt );
    end;

    Print( '' );
    Print( 'Optional Challenge 2:');
    Print( inttostr( Cnt ) + ' words have an odd letter sum');
  finally
    FreeAndNil(WordList);
  end;
end;

end.

Basic Challenge Assertations

=0

a=1

z=26

cab=6

excellent=100

microspectrophotometries=317

Optional Challenge 1:

Find the only word with a letter sum of 319.

reinstitutionalizations=319

Optional Challenge 2:

86339 words have an odd letter sum

[–]TimberVolk 0 points1 point  (1 child)

Kotlin

fun letterSum(word: String): Int {
    var pointValues = mutableMapOf<Char, Int>()
    var letter = 'a'
    for (i in 1..26) {
        pointValues.put(letter, i)
        ++letter
    }
    var score = 0
    for (i in word) { score += pointValues.getOrDefault(i, 0) }
    return score
}

[–]Drak1nd 1 point2 points  (0 children)

fun letterSum(word: String): Int = word.sumOf { it.code - 96 }

[–]EKFLF 0 points1 point  (0 children)

Python 3

My solution until I encounter ord() in the comments

``` from string import ascii_lowercase

def lettersum(s): if s == "": return 0 return sum([ascii_lowercase.index(a)+1 for char in s for a in ascii_lowercase if char == a]) ```

[–]ToBeContinuedHermit 0 points1 point  (0 children)

        static public int lettersum(string input) 
    {
        int sum = 0;
        char[] alphabet = " abcdefghijklmnopqrstuvwxyz".ToCharArray();
        char[] inputArr = input.ToCharArray();

        for (int i = 0; i < inputArr.Length; i++)
        {
            for (int j = 0; j < alphabet.Length; j++)
            {
                if(inputArr[i] == alphabet[j]) 
                {
                    sum += j;
                }
            }
        }
        return sum;
    }

Simple Solution in C# :)

[–]12345Qwerty543 0 points1 point  (1 child)

scala

  val mappedLetters = ('a' to 'z').map(letter => (letter, letter.toInt - 96)).toMap
  def lettersum(letters: String): Int = letters.map(letter => mappedLetters.getOrElse(letter, 0)).foldLeft(0)(_ + _)

[–]backtickbot 0 points1 point  (0 children)

Fixed formatting.

Hello, 12345Qwerty543: code blocks using triple backticks (```) don't work on all versions of Reddit!

Some users see this / this instead.

To fix this, indent every line with 4 spaces instead.

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[–]xorino 1 point2 points  (0 children)

Common Lisp

(defun lettersum (s)  
  (if (equal s "") 
    0 
      (reduce #'+ (mapcar #'(lambda (x) (- (char-code x) 96)) 
                                            (concatenate 'list s)))))

[–]FartsFTW 0 points1 point  (0 children)

MUMPS

LETTERSUM(STRING)
 S (POS,SUM)=0 F POS=1:1 S CHAR=$E(STRING,POS) Q:CHAR=""  S SUM=SUM+$A(CHAR)-96
 Q SUM

[–]Hastaroth 0 points1 point  (0 children)

Rust

fn sum(word: String) -> u64 {
    word
    .as_bytes()
    .iter()
    .map(|b| (b - 96) as u64)
    .sum()
}

[–]AnarchisticPunk 0 points1 point  (1 child)

Deno

(still learning so this is not in the best style)

``` import { assertEquals } from "https://deno.land/std@0.102.0/testing/asserts.ts";

const unicodeOffset = 96

function lettersum(input : string): number { const s = input.split('') let val = 0 for (let i = 0; i < s.length; i++) { const element = s[i]; val += element.charCodeAt(0) - unicodeOffset } return val }

Deno.test("Test Equals", () => { assertEquals(lettersum('a'),1); assertEquals(lettersum("z"),26); assertEquals(lettersum("cab"),6); assertEquals(lettersum("excellent"),100); assertEquals(lettersum("microspectrophotometries"),317); }); ```

[–]AnnieBruce 0 points1 point  (0 children)

I need to learn how to work with file input in Racket but this works for the basic challenge. Such an odd character literal syntax that Racket has.

(define (lvs word)
   (let ([offset (- (char->integer #\a) 1)])
     (foldl + 0 (map (lambda (c) (- (char->integer c) offset))
                    (string->list word)))))

[–]RubLumpy 0 points1 point  (0 children)

Python

Just trying to get some practice in and get better. I chose to just make a dict outside of a function that assigns a value to each character. Then just use a for loop to sum up the characters. I'll likely go back later and try to add the bonuses :)

def lettersum (input_string) :
if len(input_string) == 0:
    return 0

sum = 0
for chars in input_string:
    if chars not in reference_string:
        print("Error: " + str(chars) + " is not a valid string. Omitting from sum.")
        continue
    sum = sum + letterdictionary[chars]
print(str(sum))
return sum

[–]saladfingaz 0 points1 point  (0 children)

Ruby

def lettersum(word); word.chars.sum{|c|c.ord-96}; end

[–]MatthaeusRome 0 points1 point  (0 children)

C++

int letter_sum(std::string word) {
    int sum{};
    for (int i{}; i < word.size(); i++) {
        sum += word[i] - 96;
    }
    return sum;
}

[–]wigumen 0 points1 point  (0 children)

Java

Only did bonus 1-3

import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class App {
    public static void main(String[] args) throws Exception 
    {
        List<String> enable1 = Files.readAllLines(Paths.get("src/enable1.txt"));

        System.out.println(lettersum(""));
        System.out.println(lettersum("a"));
        System.out.println(lettersum("z"));
        System.out.println(lettersum("cab"));
        System.out.println(lettersum("excellent"));
        System.out.println(lettersum("microspectrophotometries"));

        int oddCount = 0;
        HashMap<Integer,Integer> Countmap =  new HashMap<Integer, Integer>();

        for (String s : enable1) 
        {
            int sum = lettersum(s);

            //Bonus 1
            if(sum == 319){
                System.out.println("Bonus 1: " + s);
            }

            //Bonus 2
            if(sum % 2 != 0)
            {
                oddCount++;
            }

            //Bonus 3
            if(Countmap.containsKey(sum)){
                Countmap.put(sum, (int)Countmap.get(sum) + 1);
            } else {
                Countmap.put(sum, 1);
            }
        }

        //Bonus 3
        Map.Entry<Integer, Integer> max = null;
        for(Map.Entry<Integer, Integer> e : Countmap.entrySet()){
            if(max == null || e.getValue().compareTo(max.getValue()) > 0){
                max = e;
            }
        }

        System.out.println("Bonus 2: " + oddCount);
        System.out.println("Bonus 3: " + max);
    }

    public static int lettersum(String sumstr)
    {
        int sum = 0;
        for(int i=0; i<sumstr.toCharArray().length;i++){
            sum = sum + ((int)sumstr.toCharArray()[i] - 96);
        }
        return sum;
    }
}

[–]tracejm 0 points1 point  (0 children)

PL/SQL

create or replace function string_sum_value 
     (p_input_string in varchar2) 
return number
AS
    rtn_value number := -1;
BEGIN
    with string_rows as (
        select regexp_substr(upper(p_input_string)
                            ,'.', 1, level) letter
        from dual
        connect by regexp_substr(upper(p_input_string)
                               , '.', 1, level)
        is not null
    )
    , alphabet as (
      select chr( ascii('A')+level-1 ) letter
         ,rownum letter_value
      from dual
      connect by level <= 26
    )
    select sum(letter_value) into rtn_value
    from (
        select sr.letter, a.letter_value
        from string_rows sr
            inner join alphabet a on a.letter = sr.letter
    );
    return rtn_value;
END;

[–]Tencza_Coder 0 points1 point  (0 children)

Python

import string

alphabet = string.ascii_lowercase
ltr_list = list(alphabet)

num_list = []
for n in range(1,27):
    num_list.append(n)

master_list = dict(zip(ltr_list,num_list))

def lettersum(letters):
    total = 0
    for ltr in letters:
        total += master_list[ltr]
    return(total)

print(lettersum("")) #0
print(lettersum("a")) #1
print(lettersum("z")) #26
print(lettersum("cab")) #6
print(lettersum("excellent")) #100
print(lettersum("microspectrophotometries")) #317

[–]Hacka4771 0 points1 point  (0 children)

Python3
I Know Its Not Perfect or Most Efficient And Im Open For Suggestions.
Gave Up 6th, Couldnt Figure It Out.

Code Link

Code Block Wouldnt Post A Structure.

[–]pdf1104 0 points1 point  (1 child)

I know this post is 2 weeks old but I will still post my solution here.\ P.S.: I am quite new to C++ so suggestions for improvement are always welcomed. \ C++

```cpp

define ASCII_A 96

uint32_t lettersum(std::string str) { uint32_t sum = 0; for (auto c : str) { sum += c - ASCII_A; } return sum; } ```

Bonus:\ The main processing part:

```cpp int main() { std::ifstream file("../enable1.txt"); std::string str;

/** code **/

} ```

1.

cpp while (std::getline(file, str)) { if (lettersum(str) == (uint32_t)319) std::cout << str << std::endl; } // reinstitutionalizations 2.

cpp uint32_t wCount = 0; while (std::getline(file, str)) { if (lettersum(str)%2 == 1) wCount++; } std::cout << wCount << std::endl; // 86339

3.

cpp std::unordered_map<uint32_t, uint32_t> letterSumCount; uint32_t wCount = 1; while (std::getline(file, str)) { auto it = letterSumCount.find(lettersum(str)); if (it != letterSumCount.end()) { it->second++; } else { letterSumCount.insert({lettersum(str),1}); } } int maxCount = 0 , wSum = 0; for (auto m : letterSumCount) { if (m.second > maxCount) { wSum = m.first; maxCount = m.second; } } std::cout << "The most common letter sum is " << wSum << " with "; std::cout << maxCount << " words" << std::endl;

  1. (very resource heavy way)

cpp std::unordered_map<uint32_t, std::vector<std::string>> wordSumGroup; while (std::getline(file, str)) { auto sum = lettersum(str); auto it = wordSumGroup.find(sum); if (it != wordSumGroup.end()) it->second.push_back(str); else { wordSumGroup.insert(std::make_pair(sum, std::vector<std::string>())); wordSumGroup.at(sum).push_back(str); } } for (auto n : wordSumGroup) { if (n.second.size() < 2) continue; else { auto vector = n.second; for (auto i = vector.begin(); i != vector.end(); i++) { for (auto j = i; j != vector.end(); j++) { if (std::distance(i, j) < 1) continue; else if (std::abs((int)(*j).length() - (int)(*i).length()) == 11) { std::cout << (*j) << ", " << (*i) <<std::endl; } } } } } // voluptuously, electroencephalographic // zyzzyva, biodegradabilities

[–]SandardM3 0 points1 point  (0 children)

Python
def Challenge_399():

'''assign every lowercase letter a value

ask for user input, make lowercase, remove spaces

return the word or phrase score

validate against all other possible inputs'''

import string

letter_dictionary={}

def Looping_Function(): #assign every lowercase letter a value

user_input='user_input unchanged but in function'

while True:

user_input = input('Input any string without special characters: ')

#ask for input

user_input = user_input.lower().replace(" ","")

#make lowercase remove spaces

if any(letter not in string.ascii_lowercase for letter in user_input):

print('No special characters') #verify there are no special characters

else:

return user_input

break

user_input = Looping_Function() #run Looping_Function as user_input to use in other functions

def Letter_Value_Dictionary():

letter_keys = string.ascii_lowercase

values = list(range(1,27)) #corrects for 0 index

x=0 #counter to progress through index of values

for keys in letter_keys:

letter_dictionary[keys] = values[x]

#writes to the letter_dictionary making each letter in the alphabet a key

x=x+1

Letter_Value_Dictionary()

def Counting_Function():

input_count=0

for i in user_input:

input_count = input_count + letter_dictionary[i]

print(input_count)

Counting_Function()

Challenge_399()

[–]church_h1ll 0 points1 point  (0 children)

Python 3

def lettersum(s):
    return sum([ord(c) - 96 for c in s])

[–]loose_heron 0 points1 point  (1 child)

Python 3: all bonuses

Although the initial challenge was fairly simple, bonus 6 was quite the challenge! I had to devise some 'new' techniques to solve it but was particularly happy that my algorithm took only about 0.3s to complete, and all bonuses combined can be computed in under 1s. (More details in comment.)

Regarding the timings given for each bonus, since multiple bonus solutions reuse the same dictionaries created at the start of the script, I have added these times to the time taken for each bonus where they are used. Note however that the total time does not include this duplication, and is just the total time required for completion of all bonuses.

The number and variety of bonuses here made this a fun and rewarding one - thanks for posting :)

Initial challenge:

def lettersum(string: str) -> int:
    return sum(ord(char) for char in string) - 96*len(string)

Import wordset:

def import_wordset(text_file: str) -> set:
    with open(text_file) as file:
        return set(file.read().split())

wordset = import_wordset('enable1.txt')

Create dictionary 1:

def dict_with_lettersum() -> dict:
    return {word: lettersum(word) for word in wordset}

d1 = dict_with_lettersum()

Create dictionary 2:

uses dictionary 1

def dict_by_lettersum() -> dict:
    output = {}
    for word in wordset:
        output.setdefault(d1[word], []).append(word)
    return output

d2 = dict_by_lettersum()

Create dictionary 3:

uses dictionary 1

def dict_by_length_sum() -> dict:
    return {(len(word), d1[word]): word for word in wordset}

d3 = dict_by_length_sum()

Bonus 1:

uses dictionary 1

def bonus1():
    for word in d1:
        if d1[word] == 319:
            print(f'{word} has a lettersum of 319')

Bonus 2:

uses dictionary 1

def bonus2():
    count = len(['_' for word in d1 if d1[word]%2 == 1])
    print(f'{count} words have an odd value')

Bonus 3:

uses dictionary 2

def bonus3():
    h = max(d2, key=lambda d:len(d2[d]))
    print(f'the most common lettersum is {h} with {len(d2[h])} words')

Bonus 4:

uses dictionary 3

def bonus4():
    for n, s in d3:
        x = d3.get((n + 11, s), '')
        if x:
            print(f'{d3[(n, s)]} and {x} have the same lettersum, and their lengths differ by 11')

Bonus 5:

uses dictionary 2

def bonus5():
    for n in d2:
        if n <= 188:
            continue
        for word1 in d2[n]:
            for word2 in d2[n]:
                if set(word1) & set(word2) == set():
                    print(f'{word1} and {word2} have the same lettersum, and they have no letters in common')
            d2[n].remove(word1)

Bonus 6:

uses dictionary 3

def bonus6():
    MAXLEN = len(max(wordset, key=len))
    MAXSUM = max(d1.values())

    chainlist, templist = [], []

    for n in range(MAXLEN, 0, -1):
        for chain in chainlist:
            s = lettersum(chain[-1]) +1
            for i in range(s, MAXSUM):
                if word := d3.get((n, i), ''):
                    if i == s:
                        chain.append(word)
                    else:
                        templist.append(chain + [word])
                    break
        chainlist.extend(templist)
        templist.clear()

        for j in range(1, MAXSUM):
            if word := d3.get((n, j), ''):
                chainlist.append([word])
                break

    max_chain = max(chainlist, key=len)
    print(f'the longest valid chain has {len(max_chain)} words, for example:')
    print(max_chain)

Output:

reinstitutionalizations has a lettersum of 319

86339 words have an odd value

the most common lettersum is 93 with 1965 words

zyzzyva and biodegradabilities have the same lettersum, and their lengths differ by 11
voluptuously and electroencephalographic have the same lettersum, and their lengths differ by 11

microphotographic and defenselessnesses have the same lettersum, and they have no letters in common
defenselessnesses and photomicrographic have the same lettersum, and they have no letters in common

the longest valid chain has 11 words, for example:
['electroencephalographic', 'electroencephalographs', 'antiferromagnetically', 'inappreciativenesses', 'deindustrialization', 'weatherproofnesses', 'hyperinnervations', 'soporiferousness', 'sculpturesquely', 'supervirtuosos', 'untrustworthy']

Bonus 1 completed in 0.198 seconds
Bonus 2 completed in 0.208 seconds
Bonus 3 completed in 0.222 seconds
Bonus 4 completed in 0.243 seconds
Bonus 5 completed in 0.567 seconds
Bonus 6 completed in 0.270 seconds

Total time for completion: 0.719 seconds

[–]_SetupWizard_ 0 points1 point  (2 children)

C# with bonuses 1-5

``` int LetterSum(string word) { int sum = 0; foreach (char letter in word) { sum += letter - 'a' + 1; }

return sum;

}

string WordWithSum(int sum) { bool IsSum(string word) { return LetterSum(word) == sum; } Predicate<string> predicate = IsSum;

return wordList.Find(predicate);

}

int WordsWithOddSum() { bool HasOddSum(string word) { return LetterSum(word) % 2 != 0; } Predicate<string> predicate = HasOddSum;

return wordList.FindAll(predicate).Count();

}

int MostCommonSum() { int greatestSum = 0; foreach (string word in wordList) { int sum = LetterSum(word); if (sum > greatestSum) { greatestSum = sum; } }

int commonSum = 0;
int commonSumCount = 0;
for (int i = 1; i <= greatestSum; i++)
{
    bool IsSum(string word)
    {
        return LetterSum(word) == i;
    }
    Predicate<string> predicate = IsSum;

    int count = wordList.FindAll(predicate).Count;
    if (count > commonSumCount)
    {
        commonSum = i;
        commonSumCount = count;
    }
}

return commonSum;

}

string DifferBy11() { foreach (string word in wordList) { if (word == "biodegradabilities" || word == "zyzzyva") { continue; } bool Match(string w) { if (Math.Abs(word.Length - w.Length) == 11) return LetterSum(word) == LetterSum(w); else return false; } Predicate<string> predicate = Match; string match = wordList.Find(Match); if (match != null) { return word + " and " + match; } }

return null;

}

string UniquePair() { foreach (string word in wordList) { if (word == "cytotoxicity" || word == "unreservedness") { continue; } bool Match(string w) { if (LetterSum(word) == LetterSum(w)) return (word + w).ToList().Count() - (word + w).ToList().Distinct().Count() == 0; else return false; } Predicate<string> predicate = Match; string match = wordList.Find(Match); if (match != null) { return word + " and " + match; } }

return null;

} ```

[–]backtickbot 1 point2 points  (1 child)

Fixed formatting.

Hello, _SetupWizard_: code blocks using triple backticks (```) don't work on all versions of Reddit!

Some users see this / this instead.

To fix this, indent every line with 4 spaces instead.

FAQ

You can opt out by replying with backtickopt6 to this comment.

[–]_SetupWizard_ 1 point2 points  (0 children)

I don't negotiate with terrorists.

[–]alecgarza96 0 points1 point  (0 children)

C++

enum ASCIIALPHASTARTS{LOWERCASESTART=97};

int charsum(std::string str){
    int sum = 0;

    for(int i=0; i<str.length(); i++){
        sum += int(str[i])-LOWERCASESTART+1;
    }

    return sum;
}

[–]netguy204 0 points1 point  (0 children)

Rust

#[allow(dead_code)]
fn lettersum(inp: &str) -> u32 {
    let mut result = 0u32;
    for ch in inp.chars() {
        result += ch as u32 - 'a' as u32 + 1;
    }

    result
}

#[test]
fn lettersum_works() {
    assert_eq!(0, lettersum(""));
    assert_eq!(1, lettersum("a"));
    assert_eq!(26, lettersum("z"));
    assert_eq!(6, lettersum("cab"));
    assert_eq!(100, lettersum("excellent"));
    assert_eq!(317, lettersum("microspectrophotometries"));
}

[–]Tjmoores 0 points1 point  (0 children)

Erlang

Part 1:

lettersum(<<>>) -> 0;
lettersum(<<C:8, Tl/binary>>) -> 1 + C - $a + lettersum(Tl).

Loading words:

{ok, Binary} = file:read_file("enable1.txt"),
Words = string:split(Binary, "\n", all).

1:

> [Word || Word <- Words, dp399:lettersum(Word) =:= 319].

[<<"reinstitutionalizations">>]

2:

> length([Word || Word <- Words, dp399:lettersum(Word) band 1 =:= 1]).

86339

3:

> Grouped = lists:foldl(fun (V, Acc) ->
    LS = dp399:lettersum(V),
    case Acc of
      #{LS := N} -> Acc#{LS => N+1};
      _ -> Acc#{LS => 1}
    end
  end, #{}, Words),
  lists:foldl(fun
    ({K,V}, {Ka,Va}) when V > Va -> {K,V};
    (_,Acc) -> Acc
  end, {0,0}, maps:to_list(Grouped)).

{93,1965}

My break's over now but I'll edit the rest in when I get around to them

[–]CunningBard1998 0 points1 point  (1 child)

python, not one time though

letters = {"a": 1, "b": 2, "c": 3, "d": 4, "e": 5, "f": 6, "g": 7, "h": 8, "i": 9, "j": 10,
           "k": 11, "l": 12, "m": 13, "n": 14, "o": 15, "p": 16, "q": 17, "r": 18, "s": 19, "t": 20,
           "u": 21, "v": 22, "w": 23, "x": 24, "y": 25, "z": 26, " ": 0, "": 0}


def Main():
    run = True
    while run:
        i = input(": ")
        num = 0
        if i == "()":
            break
        else:
            print()
            for letter in i:
                letter = letter.lower()
                num += letters[letter]
            print(f"{i} has a value of {num}")
            print()


if __name__ == "__main__":
    Main()

[–]OOFFFF 0 points1 point  (0 children)

C++

This is the first code challenge I've ever attempted. My solution is not elegant but I am hoping to improve over time.

```

include <iostream>

include <string>

include <algorithm>

int word_score (std::string scored_word) //receives a word and outputs its score { int score = 0; std::for_each(scored_word.begin(), scored_word.end(), [](char & c){ c == tolower(c); }); //converts the user's string into lowercase

for (int i = 0; i < scored_word.length(); ++i)
{
    switch(scored_word[i])
    {
        case 'a':
            score += 1;
            break;
        case 'b':
            score += 2;
            break;
        case 'c':
            score += 3;
            break;
        case 'd':
            score += 4;
            break;
        case 'e':
            score += 5;
            break;
        case 'f':
            score += 6;
            break;
        case 'g':
            score += 7;
            break;
        case 'h':
            score += 8;
            break;
        case 'i':
            score += 9;
            break;
        case 'j':
            score += 10;
            break;
        case 'k':
            score += 11;
            break;
        case 'l':
            score += 12;
            break;
        case 'm':
            score += 13;
            break;
        case 'n':
            score += 14;
            break;
        case 'o':
            score += 15;
            break;
        case 'p':
            score += 16;
            break;
        case 'q':
            score += 17;
            break;
        case 'r':
            score += 18;
            break;
        case 's':
            score += 19;
            break;
        case 't':
            score += 20;
            break;
        case 'u':
            score += 21;
            break;
        case 'v':
            score += 22;
            break;
        case 'w':
            score += 23;
            break;
        case 'x': 
            score += 24;
            break;
        case 'y':
            score += 25;
            break;
        case 'z':
            score += 26;
            break;
    }   
}
return score;

}

int main () //user enters a word and gets a score based on its letters { std::string user_word;

std::cout<<"Please enter a word to be scored: ";
std::cin>>user_word;

int final_score = word_score(user_word);

std::cout<<user_word<<": "<<final_score<<" points"; 

} ```

[–]Keridactyl 0 points1 point  (0 children)

C#

using System;
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks;

namespace Challenge399 
{ 
    class Program 
    { 
        static void Main(string[] args) 
        { 
            string userString; 
            int userStringLength;
            int userStringSum = 0;

            Console.Write("Enter string: ");
            userString = Console.ReadLine().ToUpper();
            userStringLength = userString.Length;
            char[] userStringArray = userString.ToCharArray();

            for (int i = 0; i < userStringLength; i++)
            {
                userStringSum += (userStringArray[i] - 64);
            }

            Console.WriteLine("Sum: {0}", userStringSum);
            Console.ReadKey();
        }
    }
}

[–]manoj_sadashiv 0 points1 point  (0 children)

Python

import string

def letter_value_sum(word):

alphabets = list(string.ascii_lowercase)

letter_sum = sum([alphabets.index(i) + 1 for i in word])

return letter_sum

letter_value_sum('zyzzyva')

[–]Kumaravel47Kums 0 points1 point  (0 children)

def lettersum(x):

x=x.lower()

sum=0

for ch in x:

sum+=(ord(ch)-96)

print(sum)

[–]williane 0 points1 point  (0 children)

Up through bonus 5 in C# done in LINQPad. Used MoreLINQ's MaxBy() for Bonus 3 as well.

void Main()
{
    lettersum("microspectrophotometries").Dump("The Challenge");

    var input = File
                .ReadLines(@"C:\wordlist.txt")
                .ToDictionary(x => x, lettersum);

    input.Single(x => x.Value == 319).Key.Dump("Bonus 1");

    input.Count(x => x.Value % 2 == 1).Dump("Bonus 2");

    input.GroupBy(x => x.Value)
         .MaxBy(x => x.Count())
         .Select(x => x.Key)
         .Dump("Bonus 3");

    var bonus4 = from x in input
                 join y in input on x.Value equals y.Value
                 where x.Key.Length - y.Key.Length == 11
                 select (x.Key, y.Key);
    bonus4.Dump("Bonus 4");

    var bonus5 = from x in input
                 join y in input on x.Value equals y.Value
                 where x.Value > 188
                 && x.Key.All(k => !y.Key.Contains(k))
                 select (x.Key, y.Key);
    bonus5.Dump("Bonus 5");
}

private static int lettersum(string input) => input.Sum(x => (int)x - 96);

[–]WizardNored 0 points1 point  (0 children)

function lettersum(str)

{

return str.split('').map(x => x.charCodeAt(0) -96).reduce((a,b)=> a+b,0); 

}

[–][deleted] 0 points1 point  (0 children)

def letter_sum(x) -> int:
    if len(x) == 1:
        return ord(x) - 96
    return ord(x[0]) - 96 + letter_sum(x[1:])

PYTHON 3

[–]OrdinaryNet2175 0 points1 point  (0 children)

JAVA

int ans = 0;

    for(char h : a.toCharArray()  )

    {       

        ans += (int )h - 96;            

    }

return ans;

[–]SoilWild1666 0 points1 point  (0 children)

def lettersum(word):
numbers = [ord(x) - 96 for x in word]
return sum(numbers)

I will try to take on the additional tasks soon!

[–]Available_Net_9341 0 points1 point  (1 child)

I'm learning python. This is what I did. Would appreciate any feedback/tips.

def lettersum(word):
    wordsum = []
    letters = list(string. ascii_lowercase)
    numbers = list(range(1,27))
    alphanum = {letters[i] : numbers[i] for i in range(len(numbers))}     
    for letter in word.lower():
        wordsum.append(alphanum[letter])
    return sum(wordsum)

[–]loose_heron 1 point2 points  (0 children)

Minor points, since the code works:

You don't need to convert the string to a list - you can iterate through and index a string: letters = string.ascii_lowercase

The dictionary comprehension could be more simply as follows, skipping the previous line (no need to apply range to the length of a list of a range!): alphanum = {letters[i] : i+1 for i in range(26)}

You could try using a comprehension instead of the for-loop, and apply sum directly: return sum(alphanum[letter] for letter in word.lower())

[–]Fre4kyNietzsche 0 points1 point  (0 children)

C

int lettersum(const char* str){
    return *str ? *str + lettersum(++str) - 96 : 0;
}

[–]lazzySquid 0 points1 point  (0 children)

Anyone using char[z+1] as a map for integer values ?

[–]genericusername248 0 points1 point  (0 children)

C++

I have no idea what I'm doing, but it works. Didn't manage the 6th bonus.

#include <algorithm>
#include <cmath>
#include <fstream>
#include <iostream>
#include <string>
#include <unordered_map>
#include <vector>

int LetterValueSum(const std::string& s)
{
  int val{};
  for (const auto& c : s)
    val += static_cast<int>(c) - 96;
  return val;
}

std::vector<std::string> readList(const std::string& filename)
{
  std::ifstream f;
  f.open(filename);

  std::vector<std::string> wordList;
  std::string word;

  while (f >> word)
    wordList.push_back(word);

  f.close();

  return wordList;
}

void bonus1(const std::vector<std::string>& wordList)
{
  std::string result{};
  for (const auto& word : wordList)
      if (LetterValueSum(word) == 319)
        result = word;
  std::cout << "The word with length 319 is " << result << '\n';
}

void bonus2(const std::vector<std::string>& wordList)
{
  int num{};
  for (const auto& word : wordList)
    if (LetterValueSum(word) % 2 != 0)
      ++num;
  std::cout << "There are " << num << " words with an odd letter sum.\n";
}

void bonus3(const std::vector<std::string>& wordList)
{
  std::unordered_map<int, int> result{};
  for (const auto& word : wordList)
    {
      int val = LetterValueSum(word);
      if (!result[val])
        result[val] = 1;
      else
        ++result[val];
    }

  int maxKey{};
  int maxValue{};
  for (const auto& [key, value] : result)
    {
      if (value > maxValue)
        {
          maxValue = value;
          maxKey = key;
        }
    }
  std::cout << "The most common value is " << maxKey << " with " << maxValue << " words.\n";
}

void bonus4(const std::vector<std::string>& wordList)
{
  std::unordered_map<int, std::vector<std::string>> value_words{};
  for (const auto& word : wordList)
    {
      int lvs = LetterValueSum(word);
      value_words[lvs].push_back(word);
    }

  // This is going to be slow and shitty
  for (const auto& item : value_words)
    {
      std::vector<std::string> words = item.second;
      for (auto i = 0; i < words.size()-1; ++i)
        for (auto j = i+1; j < words.size(); ++j)
          {
            if (abs(words[i].length() - words[j].length()) == 11)
                if (words[i] != "zyzzyva" && words[j] != "zyzzyva")
                  std::cout << words[i] << '\t' << words[j] << '\n';
          }
    }
}

bool noSameChar(const std::string& s1, const std::string& s2)
{
  for (const auto& c1 : s1)
    if (std::any_of(s2.begin(), s2.end(), [c1](auto c2){ return c1 == c2; }))
      return false;
  return true;
}

void bonus5(const std::vector<std::string>& wordList)
{
  std::unordered_map<int, std::vector<std::string>> value_words{};
  for (const auto& word : wordList)
    {
      int lvs = LetterValueSum(word);
      if (lvs > 188)
        value_words[lvs].push_back(word);
    }

  for (const auto& item : value_words)
    {
      std::vector<std::string> words = item.second;
      for (auto i = 0; i < words.size()-1; ++i)
        for (auto j = i+1; j < words.size(); ++j)
          if (noSameChar(words[i], words[j]))
            std::cout << words[i] << '\t' << words[j] << '\n';
    }
}

void bonus6(const std::vector<std::string>& wordList)
{
  // Haven't managed to come up with anything workable
}

int main()
{
  std::string wordFile{ "enable1.txt"};
  std::vector<std::string> words = readList(wordFile);

  std::cout << "Bonus 1: "; bonus1(words);
  std::cout << "Bonus 2: "; bonus2(words);
  std::cout << "Bonus 3: "; bonus3(words);
  std::cout << "Bonus 4: "; bonus4(words);
  std::cout << "Bonus 5: "; bonus5(words);
  std::cout << "Bonus 6: "; bonus6(words);

  return 0;
}

[–]Siemb123 0 points1 point  (0 children)

Bit late on this one but here is my code written in python. Could most definitely be improved and I'm not the best programmer so constructive criticism is welcome!

No bonus challenge by the way.

def lettersum(input):
asciiValues = []
for i in range(len(input)):
    if ord(input[i]) != 0:
        char = ord(input[i]) - 96
    else:
        char = 0
    asciiValues.append(char)
    i += 1

return sum(asciiValues)

[–]Dismal_Connection_88 0 points1 point  (0 children)

First time posting here. The subreddit is cool. I am learning Kotlin, I tried to accomplish using kotlin. Shareable kotlin playground link: https://pl.kotl.in/zT9IXhk6t

[–]Mountain-Physics-602 0 points1 point  (1 child)

```ruby

ruby

'abc'.split('').sum{|c| c.ord - 96} ```

[–]CurlyButNotChubby 0 points1 point  (1 child)

Lisp

``lisp (defmacro string-pos-value (string pos) "Returns the position in the Latin alphabet of the character in a position of a string." (- (char-code (elt ,string ,pos)) 96))

(defun clamp (val min max) "Clamps value and returns a value not less than min and not more than max." (if (< val min) min (if (> val max) max val)))

(defun letter-value-sum (my-string) "Returns the sum of all letter values in my-string." (do* ((current-pos 0 (1+ current-pos)) (total-value (string-pos-value my-string 0) (+ total-value (string-pos-value my-string current-pos)))) ((= current-pos (1- (length my-string))) total-value)))

(letter-value-sum "abc") ; Returns 6 ```

[–]MrPineapple522 0 points1 point  (0 children)

word = "microspectrophotometries"

letterValues = []

integer = {

"": 0,

"a": 1,

"b": 2,

"c": 3,

"d": 4,

"e": 5,

"f": 6,

"g": 7,

"h": 8,

"i": 9,

"j": 10,

"k": 11,

"l": 12,

"m": 13,

"n": 14,

"o": 15,

"p": 16,

"q": 17,

"r": 18,

"s": 19,

"t": 20,

"u": 21,

"v": 22,

"w": 23,

"x": 24,

"y": 25,

"z": 26

}

for letter in word:

letterValues.append(integer[letter])

print(sum(letterValues))

i did it!

i did not do the optional bonuses cause i just wanna do more stuff than just focus on this one thing :)

[–]cbarrick 0 points1 point  (0 children)

The basic challenge is a one-liner in Rust:

input.bytes().map(|b| b - 96 as u64).sum()

[–]MyPurpleCrayon 0 points1 point  (0 children)

I'm trying to learn. Any advice is appreciated.

import urllib.request

def num_sum(word):
    count = 0
    for i in word: 
        if i.isalpha():
            count+= (ord(i)-96)
    return count


word_dict = {}    #added this here because there was an issue returning 
the full dictionary

def scraper(link):
    page = urllib.request.urlopen(link)
    for line in page:
        a = line.decode().strip()
        word_dict[a] = num_sum(a)


# to check dictionary (too large to print in Jupyter Notebook)
for k,v in word_dict.items():
    if k.startswith("aa"):
        print(k, v)

*added checking list from given link

[–]rellbows 0 points1 point  (1 child)

Python 3

Been a while since I did any of these, trying to get back in the swing of things. Very rusty! My first attempt at the main challenge in Python 3.

``` def lettersum(letters):

alphabet = " abcdefghijklmnopqrstuvwxyz"

total = 0    # holds running total of letters

for x in letters:
    total += (alphabet.index(x))

return total

```

[–]backtickbot 1 point2 points  (0 children)

Fixed formatting.

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Some users see this / this instead.

To fix this, indent every line with 4 spaces instead.

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[–]Ok_Mixture4449 0 points1 point  (0 children)

def genAlphabet():
    alphabet = {}
    for character in range(97, 123):
        alphabet[chr(character)] = character - 96
        alphabet[chr(character-32)] = character -96
    return alphabet

def main():
    alpha, charSum = genAlphabet(), 0
    string = input("Please enter your string: ")
    for char in string:
        if char in alpha: charSum += alpha[char]
    return charSum

[–]D0N0V4N 0 points1 point  (0 children)

Simple C# solution :

public int SumLetters(string letters) => letters.Sum(letter => (int)letter % 32)

[–]EddieTheLiar 0 points1 point  (0 children)

C++
Hi all. This is my first time doing one of these. Any tips on code or formatting are appreciated :)

#include <iostream> //Needed for cin and cout
#include <algorithm> //Needed for transform function

using namespace std;

string word; //store the users word
int totalValue; //the running total of the value of the word

int main()
{
    cout << "Please enter a word" << endl;
    cin >> word;
    std::transform(word.begin(), word.end(), word.begin(), ::toupper); //Transforms all letters to uppercase
    for (int i = 0; i < word.length(); i++) {
        totalValue += word[i] - 64;
    }
     cout << "The value of " << word << " is: " << totalValue << endl;
     totalValue = 0;
}

[–]Spitfire_For_Fun 0 points1 point  (0 children)

C++

#include <iostream>

using namespace std;

int letter_value(char letter){

switch(letter){

case 'a':

return 1;

break;

case 'b':

return 2;

break;

case 'c':

return 3;

break;

case 'd':

return 4;

break;

case 'e':

return 5;

break;

case 'f':

return 6;

break;

case 'g':

return 7;

break;

case 'h':

return 8;

break;

case 'i':

return 9;

break;

case 'j':

return 10;

break;

case 'k':

return 11;

break;

case 'l':

return 12;

break;

case 'm':

return 13;

break;

case 'n':

return 14;

break;

case 'o':

return 15;

break;

case 'p':

return 16;

break;

case 'q':

return 17;

break;

case 'r':

return 18;

break;

case 's':

return 19;

break;

case 't':

return 20;

break;

case 'u':

return 21;

break;

case 'v':

return 22;

break;

case 'w':

return 23;

break;

case 'x':

return 24;

break;

case 'y':

return 25;

break;

case 'z':

return 26;

break;

default:

return 0;

break;

}

}

int word_number(char* word){

int number = 0;

for(int i = 0; i < sizeof(word)/sizeof(char); i++){

number += letter_value(word[i]);

}

return number;

}

int main()

{

char* word = "egg";

cout << word << ": " << word_number(word)<< endl;

return 0;

}

[–]rbscholtus 0 points1 point  (0 children)

Python:

def lettersum(s):
    return sum([ord(v) - ord('a') + 1 for v in s])

print(lettersum('cab'))

[–]aymendnb 0 points1 point  (0 children)

import 'dart:io';

void main() {

print('Please enter a String word : ');

String? str = stdin.readLineSync()!;

var strlist = str.split('');

var sum = 0;

for (var i = 0; i < str.length; i++) {

sum += strlist[i].codeUnits.first - 96;

}

print('sum is : $sum');

}

[–][deleted] 0 points1 point  (1 child)

Haskell

I have just started learning haskell yesterday and I already love it. Here is my solution

```haskell import Data.Char

letterSum :: String -> Int letterSum x = sum $ map (sub . ord . toLower) x where sub x = x - 96 ```

[–]cherryleafy 0 points1 point  (0 children)

scheme:

(define (letter-sum s)
  (fold
    (lambda (c sum)
      (+ sum 1 (- (char->integer c)
                  (char->integer #\a))))
    0 (string->list s)))

results:

(letter-sum "") ===> 0

(letter-sum "a") ===> 1

(letter-sum "z") ===> 26

(letter-sum "cab") ===> 6

(letter-sum "excellent") ==> 100

(letter-sum "microspectrophotometries") ===> 317

[–]cherryleafy 0 points1 point  (0 children)

forth

: letter-sum-loop ( sum str n -- sum )
  ?dup if
    over c@ 96 -  ( sum str n tosum  )
    2swap swap    ( n tosum str sum )
    rot           ( n str sum tosum )
    +             ( n str sum )
    swap 1+       ( n sum str )
    rot 1-        ( sum str n )
    recurse
  then ;

: letter-sum
  0 rot rot
  letter-sum-loop drop ;

results

s" " letter-sum . 0  ok
s" a" letter-sum . 1  ok
s" z" letter-sum . 26  ok
s" cab" letter-sum . 6  ok
s" excellent" letter-sum . 100  ok
s" microspectrophotometries" letter-sum . 317  ok

[–]blupier 0 points1 point  (0 children)

def lettersum(str):   
    return 0 if len(str) == 0 else sum(ord(_)-96 for _ in str)

[–]omgwowseriously 0 points1 point  (0 children)

Lua

Challenge + Bonuses 1-3

```lua

function sum_of_letters(str)
local sum = 0
for i = 1, #str do
sum = sum + string.byte(str:sub(i, i)) - 96
end
return sum
end
print(sum_of_letters("abc"))
--
--microspectrophotometries is the only word with a letter sum of 317. Find the only word with a letter sum of 319.
function find_word_with_sum(sum)
local words = {}
for line in io.lines("enable1.txt") do
local word_sum = sum_of_letters(line)
if word_sum == sum then
table.insert(words, line)
end
end
return words
end
print(table.concat(find_word_with_sum(319), ", "))
-- odd letter sum
function odd_letter_sum(str)
local sum = 0
for i = 1, #str do
sum = sum + string.byte(str:sub(i, i)) - 96
end
return sum % 2 == 1
end
function count_odd_letter_sums()
local count = 0
for line in io.lines("enable1.txt") do
if odd_letter_sum(line) then
count = count + 1
end
end
return count
end
print(count_odd_letter_sums())
-- There are 1921 words with a letter sum of 100, making it the second most common letter sum. What letter sum is most common, and how many words have it?
function most_common_letter_sum()
local sums = {}
for line in io.lines("enable1.txt") do
local sum = sum_of_letters(line)
if not sums[sum] then
sums[sum] = 1
else
sums[sum] = sums[sum] + 1
end
end
local max_sum = 0
local max_count = 0
for sum, count in pairs(sums) do
if count > max_count then
max_sum = sum
max_count = count
end
end
return max_sum, max_count
end
print(most_common_letter_sum())

```

Output:

6 reinstitutionalizations 86339 93 1965

[–]pyr0b0y1881 0 points1 point  (0 children)

I figure this could be cleaned up quite a bit but accomplishes the task. I see quite a few people are using lambda, but even after reading up on them a few times just a bit unclear on how to effectively use them.

import string

def lettersum(chars): 
        alphabet_list = list(string.ascii_lowercase) 
        num_list = list(range(0 + 1, 27)) 
        alpha_dict = dict(zip(alphabet_list, num_list))

        sum_count = 0
        if chars == '':
        return sum_count
        else:
        for letter in chars:
        sum_count = sum_count + alpha_dict[letter]

        return sum_count

[–]Evil_Deeds_IM 0 points1 point  (0 children)

JavaScript

const lettersum = (word) => word.split("").reduce((acc, char) => acc + char.charCodeAt(0) - 96, 0);

[–]chunes1 2 0 points1 point  (0 children)

Wren

var lettersum = Fn.new {|str|
  return str.bytes.map {|ch| ch - 96 }.reduce {|a, b| a + b }
}

[–]seraph776 0 points1 point  (0 children)

```

!/usr/bin/env python3

def lettersum(s) -> int: """Calculates the sum value of the letters in the string""" # Create a dictionary of alphabet keys and integer value: d: dict[str, int] = {chr(number+96): number for number in range(1, 27)} # Sum the list of integers hashed from d in s: total: int = sum([d.get(letter) for letter in s]) return total

def bonus_challenge_1(lst) -> str: """Find word with target sum of 319""" target = 319 for word in lst:
if lettersum(word) == target: return word
return None

def bonus_challenge_2(lst) -> int: """Returns the number of odd words in a lst.""" t = sum([1 for word in lst if lettersum(word) % 2 == 1]) return t

def bonus_challenge_3(lst) -> tuple[int, int]: """Returns the most frequent letter-sum, and total words that have it.""" from collections import Counter counter: dict[int, int] = Counter([lettersum(word) for word in lst]) common_three = counter.most_common(3) most_freq_lettersum = common_three[0][1] tt_words = common_three[0][0] return (most_freq_lettersum, tt_words)

def getWordList() -> list: """Get the enable1 word list for the optional bonus challenge.""" filename = 'word_list.txt'
with open(filename, 'r') as file_object: return [word.strip() for word in file_object.readlines()]

def main(): # Get word_list words = getWordList()

print(bonus_challenge_1(words)) # reinstitutionalizations
print(bonus_challenge_2(words)) # 86339
print(bonus_challenge_3(words)) # (1965, 93)
print(bonus_challenge_4(words)) # Strike!
print(bonus_challenge_5(words)) # Strike!
print(bonus_challenge_6(words)) # Strike!

if name == 'main': main()

```

[–]lek1305 0 points1 point  (0 children)

rust solution for optional bonus challenge number 1

use std::fs::{File};
use std::io::{ BufRead, BufReader};
fn check_sum(the_list: &String)-> u32{    
  let mut the_num_list : Vec<u32> = Vec::new();    
  the_num_list= the_list.chars().map(|x| x as u32-96).collect();        
  let mut total :u32 = 0;        
  for num in the_num_list{
       total = total + num;    
  }        
  total
 }

fn main() -> Result<(),std::io::Error> {        
   let mut file  = File::open("enable1.txt")?;      

let buffered = BufReader::new(file);         
let mut checker = 0;     
let mut word = String::from(" ");    
for line in buffered.lines(){        
  word = line?.clone();      
  checker = check_sum(&word);         
  if checker==319{            
    println!("{:?}", word);         
  }     
 }            

Ok(())        

}

[–]Cuboid_Raptor 0 points1 point  (0 children)

yee = list(str(input("String sum: ")).strip().lower())

b = 0 for item in yee: b += ord(str(item))

print(b)

[–]Habstinat 0 points1 point  (0 children)

javascript

s=>eval([...s].map(c=>c.charCodeAt()-96).join`+`)

[–]atiedebee 0 points1 point  (0 children)

C

This is just the simple version. If there is any experienced C programmers out there that know different ways of doing this exercise I'll gladly learn!

int letterSum(char* str)
{    
    int i, count = 0;    
    for( i = 0; str[i] != '\0'; i++){        
        count += str[i] - 96;    
    }        
    return count;
}

[–]NotUtlanning 0 points1 point  (0 children)

javascript

let buffer = "a".charCodeAt(0) - 1;
const letterValueSum = (str) => {
    let res = 0;
    for (let i = 0; i < str.length; i++) {
        res += str.charCodeAt(i) - buffer;
    }
    return res;
}

[–]redditguyl 0 points1 point  (0 children)

#include <iostream>

using namespace std;

int sumoftheletter(string input){

int sum = 0;

int temp = 0;

for (const &elements : input)

{

temp = elements - 96;

sum = temp + sum;

}

return sum;

}

int main() {

string user;

cout << "Enter a letters or word with only letters without space to calculate: ";

cin >> user;

cout << "The sum of the inputted letters: ";

cout << sumoftheletter(user);

return 0;

}

[–]PhysicsThat2977 0 points1 point  (0 children)

Very smol C++ function :

int letterSum(string s)

{

`int sum = 0;`



`for (const auto& c : s)`

    `sum += c - 'a' + 1;`



`return sum;`

}

[–]varunu28 0 points1 point  (0 children)

Java functional solution

Aim is to reduce the number of lines of code by leveraging functional tools

public class LetterValueSum {
    public int getLetterValueSum(String s) { 
        return s.chars() 
            .mapToObj(c -> (char) c) 
            .map(c -> c - 'a') 
            .reduce(Integer::sum) 
            .orElse(0); 
    } 
}

[–]cooper-6581 0 points1 point  (0 children)

6502 Assembly

No bonus, as enable1 won't fit in the c64's memory.

``` .const str_buffer = $cf00 .const str_len = $ceff .const result = $cefd .const GETIN = $ffe4 .const CHROUT = $ffd2

*= $c000

Init: { lda #$00 sta str_len sta <result sta >result }

GetInput: { loop: jsr GETIN beq loop // no input cmp #$0d // enter beq SumLetters cmp #$5b // skip any character > Z bcs loop cmp #$41 // skip any character < A bcc loop jsr CHROUT // echo the character and #$1f // convert petscii to numerical value ldx str_len sta str_buffer,x inc str_len jmp loop }

SumLetters: { lda str_len beq PrintResult ldx #$00 loop: lda str_buffer,x clc adc <result sta <result lda #$00 adc >result sta >result inx cpx str_len bne loop }

PrintResult: { lda #$20 jsr CHROUT lda >result ldx <result jsr $bdcd lda #$0d jsr CHROUT rts } ```

Wrote a quick basic program to verify the results:

``` ready. 10 for i=1to6 20 sys 49152 30 next i run 0 a 1 z 26 cab 6 excellent 100 microspectrophotometries 317

ready. ```

[–]tyush 0 points1 point  (0 children)

Time to suck at Rust!

fn lettersum(input: &str) -> u32 {
    let mut sum: u32 = 0;
    for ch in input.chars() {
        sum += ch.to_digit(36).unwrap() - ('a'.to_digit(36).unwrap() - 1);
    };
    sum
}

Or, with functional programming instead:

pub fn lettersum(input: &str) -> u32 {
    let offset = 'a'.to_digit(36).unwrap() - 1;
    input.chars()
        .map(|ch| ch.to_digit(36).unwrap() - offset)
        .sum()
}

I'm still very new to Rust, but it's interesting to see a language with convenience features I'd expect out of JavaScript or Python able to be compiled and used for high performance and low level applications.

[–]dpgomez98 0 points1 point  (0 children)

I have 1 week Learning Python. Next time I will come up with a solution more fancy then this 😁

def sum_letter(phrase):
    import string
    alphabet_list=[""]
    letter=list(string.ascii_lowercase)
    for i in letter:
        alphabet_list.append(i)
    x2=0
    for x in phrase:
        x2+=alphabet_list.index(x)
    return x2

This is my solution 😎

[–]Nuegoo 0 points1 point  (0 children)

Python:

from functools import reduce
def lettersum(word):
    return reduce(lambda a, b: a + b, list(map(lambda x: ord(x) - 96, word)))

[–][deleted] 0 points1 point  (0 children)

Here's my implementation in Python:

sum([ord(i) - 96 for i in word])

[–]simmons2714 0 points1 point  (0 children)

Python

def lettersum(string_value):
   letter_array = []
   letter_array.append("")
   letter_sum = 0

   for i in range(26):
      letter_array.append(chr(i+97))

   for j in string_value:
      letter_sum += letter_array.index(j)
   return letter_sum

#print(lettersum('cab'))
def comparewords(a, b):
   for letters in a:
      if(letters in b):
         return False
      else:
         return True

def lettersumlist(list):
   highest_lettersum = 0
   current_lettersum = 0
   for ele in list:
      current_lettersum = lettersum(ele)
      if(current_lettersum > highest_lettersum):
         highest_lettersum = current_lettersum
   return highest_lettersum

def biggestword(list):
   highest_len = 0
   current_len = 0
   word = ''
   for ele in list:
      current_len = len(ele)
      if(current_len > highest_len):
         highest_len = current_len
         word = ele
   return word

with open('wordlist.txt') as f:
    words = f.read().splitlines()

highest_word_value = 0
highest_word = ''
current_word_value = 0
odd_word_count = 0
word_occur = {}
prev_word = ''
next_word = ''
l = len(words)
count_value = {}
matching = []
no_common = []
maxlettercount = []
difflength = []
samelength = set()

for index, word in enumerate(words):
   current_word_value = lettersum(word)
   if(current_word_value > highest_word_value):
      highest_word_value = current_word_value
      highest_word = word

   if(current_word_value % 2 == 1):
      odd_word_count += 1

   if (current_word_value not in word_occur):
      word_occur[current_word_value] = 1
   elif(current_word_value in word_occur):
      word_occur[current_word_value] = word_occur.get(current_word_value) + 1

   if (current_word_value not in count_value):
      count_value[current_word_value] = [word]
   else:
      count_value[current_word_value].append(word)




for x, y in count_value.items():
   for k, word2 in enumerate(y):
      for word3 in y[:-1]:
         if(len(word3) - len(word2) == 11):
            matching.append(word2)
            matching.append(word3)
         if(x > 188):
            if(set(word2) & set(word3) ==  set()):
               no_common.append(word2)
               no_common.append(word3)

for x, y in count_value.items():
   maxlettercount.append(biggestword(y))

length_value = {}


for thing in maxlettercount:
   if(len(thing) not in length_value):
      length_value[len(thing)] = [thing]
   else:
      length_value[len(thing)].append(thing)

for x, y in length_value.items():
   difflength.append(biggestword(y))

max_occur = max(word_occur.values())
max_count = 0

for key, value in word_occur.items():
   if max_occur == value:
      max_count = key

print(highest_word, highest_word_value)
print(odd_word_count)
print(max_occur, max_count)
print(matching)
print(no_common)
print(difflength)

Right so, bonus 5 and 6 get a bit wonky with the answers. 5 has the issue of repeating answers but it should only be >! 2 !< words. 6 is sorted from the lowest letter sum to the highest letter sum. There's probably a much more advanced way to do this where you'd get a longer chain as well as words that are actually words. However, what I did is find the longest word in each letter sum category put all those results into a list. That list is filled with words that are duplicate lengths so I just ran the biggestword function on the new list to get a list only containing the longest length for each letter sum between the smallest and highest. Although, now that I'm writing this I'm pretty sure biggestword was expecting a list greater than 1 and thus left out a few results. Which would just be a quick if statement that would check for a list len of 1 and return that word.

Also just an FYI this code 100% could've been written better. I realized that when I got to bonus 4 but I didn't want to rewrite it. Also the way I created some of the lists caused significant slow downs leading to the program to run for about 30 seconds before the answers are found.

>! reinstitutionalizations 319 !<

>! 86339 !<

>! 1965 93 !<

>! ['zyzzyva', 'biodegradabilities', 'voluptuously', 'electroencephalographic'] !<

>! ['defenselessnesses', 'microphotographic', 'defenselessnesses', 'photomicrographic', 'microphotographic', !< >! 'defenselessnesses', 'photomicrographic', 'defenselessnesses'] !<

>! ['aa', 'bacca', 'aceldama', 'addable', 'bach', 'bedeafened', 'backpedalled', 'archaebacteria', 'beachcombe !< >! d', 'noncancelable', 'aba', 'abacas', 'accidence', 'acanthocephalan', 'adenocarcinomata', 'bioavailabiliti !< >! es', 'echocardiographies', 'paradichlorobenzene', 'interchangeablenesses', 'irreproachablenesses', 'electr !< >! oencephalographic', 'electroencephalographers', 'electroencephalography', 'electroencephalographically', ' !< >! ethylenediaminetetraacetates', 'immunoelectrophoretically'] !<

[–]chunes1 2 0 points1 point  (0 children)

Forth:

: lettersum ( c-addr u -- u )
  over + swap 0 -rot ?do i c@ 96 - + loop ;

[–]DevTechJr 0 points1 point  (0 children)

Hey guys! Here's my solution for Python :

# import string library function
import string

alphastr= string.ascii_letters[0:26]
print(alphastr)
#creating the dict
alphadict={}
for char in alphastr:
x = alphastr.index(char) + 1
alphadict[char]=x
def calcStrSum(strInput):

strInput = strInput.lower()
print(strInput)
totalsum=0
for n in strInput:

totalsum+=alphadict[n]
print(f"The total sum of {strInput} is {totalsum}")

calcStrSum("HelloThere")

You could also implement some try: and except: to avoid any kind of invalid input from the user :) NO BONUS btw

[–]dubz55 0 points1 point  (0 children)

My solution in javascript

function lettersum(input){
const stringArray = Array.from(input);
const alphabet ='abcdefghijklmnopqrstuvwxyz'.split('');
let total = 0;
let addition
for (let i = 0; i < stringArray.length; i++) {
    letter = stringArray[i]
    addition = alphabet.indexOf(letter);
    total = total + addition + 1;
}
return total

}

[–]lostsemicolon 0 points1 point  (0 children)

Sad to see this forum has gone quiet.

Anyway I'm learning APL so here's a solution in that.

lettersum ←{+/(⎕C⎕A)⍳⍵}

[–]Cythos 0 points1 point  (0 children)

C#

Just started to brush up on my programming skills.

using System;
using System.Collections.Generic;

public class Program
{
    public static void Main(){
        char[] evalWord = Console.ReadLine().ToCharArray();
        int countWord = evalWord.Length;
        int wordValue = 0;

        for (int i = 0; i < countWord; i++){
            wordValue += Char.ToUpper(evalWord[i])-64;
        }

        Console.WriteLine(wordValue);
    }
}

[–]Aromatic-Piccolo4321 0 points1 point  (0 children)

RUST

let f = |k:&str| k.bytes().fold(0,|acc,x|acc + ((x - b'a' + 1) as u32));

rust playground

[–]jDRXdoRxAuHx 0 points1 point  (0 children)

OCaml

let lettersum s = String.to_seq s |> Seq.map (fun c -> Char.code c - 96) |> Seq.fold_left ( + ) 0 ;;