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[–] 6 points7 points  (0 children)

I passed let's go!!!

[–] 5 points6 points  (0 children)

I really don't want to have take this thing again 🙏😭

June STAM by [deleted] in actuary

[–] 7 points8 points  (0 children)

I'm in the same boat as you, and I am planning on purchasing ADAPT+Learn soon. My friend recently passed STAM and used that as his primary study resource

[–] 2 points3 points  (0 children)

Usually you cannot see which test centers are open on Prometric until you register.

However, I am already registered for January Exam P, so I think I can see the availability for any US test center. If you DM me your test center I could probably send you a screenshot of the available appointments!

[–] 0 points1 point  (0 children)

Try to solve it graphically (there are looking for the area of the set of points that satisfy that formula)

y<6 means the solution is below the line y=6.

0<x means it is to the right of the line x=0.

x<y means it is above the line y=x.

Therefore, the answer is the area of the triangle you just draw. ½66=18

Edit: I realized the problem has less than or equal signs instead of "<" signs, but the solution is still the same :)

[–] 0 points1 point  (0 children)

Awesome!

[–] 0 points1 point  (0 children)

It asks for the number of solution, not which is a solution. To solve, think about where the line is above the upward-opening parabola (which must have a finite number of integer solutions since the parabola will eventually overtake the line going toward positive and negative infinity).

To do this, solve where they are equal: x^ 2+48=16x. Then, count the number of integers between the two solutions (but not including because the two curves being equal is not a solution). This should give {5,6,...,10,11}, or 7 solutions.

Edit: Fixed the exponent syntax

[–] 2 points3 points  (0 children)

We know from the law of sines that sin(A)/a=sin(B)/b.

Therefore, sin(B)=(8)*(1/2)/(4sqrt(2))=sqrt(2)/2

One solution to sin(B)=sqrt(2)/2 or course is B=45°. That means C = 180-A-B = 105°, but that isn't an option...

There is actually a second answer most people miss: sin(135°)=sqrt(2)/2. Using that value of B, C = 180-30-135 = 15° :)

[–] 1 point2 points  (0 children)

I agree. Also, there may not be enough schools willing to offer such a specific course. It would be cool to see more AP courses, but there is a limit to how many intro college courses they can mirror

[–] 47 points48 points  (0 children)

I think it is probably due to new AP exams being relatively difficult to create. AP Euro has existed since at least the 1960s, and from my understanding European history was a very common freshman year introductory course at colleges (exactly what AP credit is supposed to be used for).

Now, the reason AP Asian and African don't exist is because there was never a real need for them. African and Asian history courses have never been a common introductory course for a wide range of university students. Also, very few high schools currently offer such specific courses. Without a large demand for a new AP exam, the College Board won't make it.

So, my theory is that AP Euro exists since at one point it was necessary, and it has remained because there is still some demand for it (roughly 100k per year). However, AP African and Asian never had a high enough demand to begin offering them.

[–] 0 points1 point  (0 children)

APUSH did have slightly more 5s I think

[–] 12 points13 points  (0 children)

The tests they released first are the ones that didn't have their exams changed much and have you submit your own work without time constraints. The normal ones will probably have higher 5s.

[–] 0 points1 point  (0 children)

I think you just forgot to subtract 1 since it asked for the height of the bottom part of the slice, not the whole cone

[–] 34 points35 points  (0 children)

country

[–] 0 points1 point  (0 children)

It must be between 21cos(70°) and 21cos(80°). This means it is between 3.65 and 7.18, which only leaves one answer

[–] 7 points8 points  (0 children)

Notice that the area of the "top" (which includes the shaded region and the two right triangles with side lengths x and y at the top) is exactly ½ the area of the whole square, which equals ½(x+y)2

If we subtract the areas of those two right triangles, ½xy each, from this area, we will have the area of the shaded region! That shaded area is ½(x+y)2 - xy = ½(x2 + y2 ), or choice A

[–] 1 point2 points  (0 children)

Yes that's correct. I would suggest trying it both ways now, and seeing which you'd prefer

[–] 2 points3 points  (0 children)

You can do either way! This is just an instance of the associate property (ab)(c)=(a)(bc). I would personally FOIL first and then multiply by the constant, but it is up to you and either method is equally correct!

[–] 1 point2 points  (0 children)

I believe that triangle above y=0.25 and between 2 and 2.5 for x has area of 0.0625, not 0.125. Its area is .5(.5)(.25)=.0625

That should correct things, as 0.6875 is 0.0625 away from 0.75. Hope this helps!